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Tatiana [17]
2 years ago
12

What are the first 6 multiples of 3?

Mathematics
1 answer:
zvonat [6]2 years ago
7 0

Answer:

1 and 3 so 3

Step-by-step explanation:

6:1,2,3,6

3:1,3

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What is ∛1728. Then multiplied by ∛14903
NeTakaya

Cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

<u>Solution: </u>

Need to calculate \sqrt[3]{1728} and then multiply the result by \sqrt[3]{14903}

Let us first evaluate \sqrt[3]{1728}

\Rightarrow \sqrt[3]{1728}=\sqrt[3]{12 \times 12 \times 12}=12

As need to multiply 12 by \sqrt[3]{14903}

\Rightarrow 12 \times \sqrt[3]{14903}

On solving \sqrt[3]{14903}, we get

\sqrt[3]{14903}=24.608

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Hence cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.

8 0
2 years ago
A candy maker is making candy canes to sell over the holidays she has 45 left over the last month sale and she can make 225 per
notsponge [240]

F(x) stands for a function, and if x stands for the number of days, than she can do 225 per day, which would be the multiplication to find the toatl 225x.

Then, with 45 extra, we add that to the equation:

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Answer: F(x) = 225x + 45

Credit to: @2Educ8

+ = <3

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3 years ago
Find the limit as limit x-&gt;0, tan2x/x
kiruha [24]
We are given with the expression <span>tan2x / x</span> and asked to evaluate the expression to limit as theta approaches zero. In this case, we substitute first zero. The answer is zero over zero. This  is indeterminate so we derive the terms accdg to L'hopital's rule. The derivative is 2 sec^2 2x/1. cos 2x is 1 so is sec^2 2x. Hence the answer is 2.
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Answer:

x+3y=7

Step-by-step explanation:

y-2= -1/3(x-1)

-3y+6= x-1

x+3y= 7

4 0
3 years ago
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