Binary search involves searching a sorted list
The number of values that will be examined is 15
<h3>How to determine the number of examined values</h3>
The equation that calculates the number of values that will be examined is:
Where n represents the number of values to examine and N represents the number of time stamps
So, we have:
Take the log of both sides
Apply the laws of logarithm
![[n - 1]\log(2) = 4](https://tex.z-dn.net/?f=%5Bn%20-%201%5D%5Clog%282%29%20%3D%204)
Divide both sides y log(2)
The next integer greater than 13.2 is 14.
So, we have:
Add 1 to both sides
Hence, the number of values that will be examined is 15
Read more about binary search at:
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<span>You can install several printers on your machine, but at least one must be the default printer.
When you have several machines attached to your computer, it is important to designate one of them as the 'default' machines so as to avoid confusion within the system. If you fail to do this, you may create some problems, so be sure to choose a default one.</span>
Answer:
trojan horse
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spyware
Explanation:
gimme the brainliest hehe
Answer:
The Answer Is False Because They Aren't Called Peripherals
Answer:
public class Main
{
public static void main(String[] args) {
System.out.println(min(3, -2, 7));
}
public static int min(int n1, int n2, int n3){
int smallest = Math.min(Math.min(n1, n2), n3);
return smallest;
}
}
Explanation:
*The code is in Java.
Create a method named min that takes three parameters, n1, n2, and n3
Inside the method:
Call the method Math.min() to find the smallest among n1 and n2. Then, pass the result of this method to Math.min() again with n3 to find the min among three of them and return it. Note that Math.min() returns the smallest number among two parameters.
In the main:
Call the method with parameters given in the example and print the result
