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Nina [5.8K]
3 years ago
10

You are configuring a wireless network with two wireless access points. Both access points connect to the same wired network. Yo

u want wireless users to be able to connect to either access point, and to be able to roam between the two access points. How should you configure the access points?
Computers and Technology
2 answers:
krok68 [10]3 years ago
7 0

Answer:

have the same SSID but different channels

Explanation:

Based on the information provided within the question it can be said that the best option to accomplish this would be to have the same SSID but different channels. This would maintain the users connected to the same network name (SSID) but still be able to roam and jump from one access point to the other.

kodGreya [7K]3 years ago
4 0

Answer:

Same SSID, different channel.

Explanation:

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anastassius [24]

Answer:

Explanation:

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2 years ago
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AysviL [449]

The invention of the micro hard drive is not a driver of wireless growth.

What is Hard Drive (HDD)?

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6 0
1 year ago
What is the function of a header when writing HTML
marusya05 [52]
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5 0
3 years ago
A method to accept the number of drawers in the desk as input from the key board. This method returns the number of drawers to t
Julli [10]

Answer:

Following code takes the information about the wood from the user, do the process of calculating the value according to there type and numbers, then add the surcharge to it while giving the answer to the user.

For differentiating the type of woof i used the if then else statement while i used switch case statement for assigning the appropriate value according to the types of the wood will be processing in the program.

The code is given below:

Explanation:

Code:

namespace std;\\ any name instead of std.

{

   class Program

   { \\ starting the main program

       static void Main(string[ ] args)

       {

           int numberOfDrawers = 0;

           string deskWoodType = "o";

           double cost = 0;

           drawersMeth(numberOfDrawers);

           woodTypeMeth(deskWoodType);

           CalculateCostMeth(numberOfDrawers, cost, deskWoodType);

           OutPutCostMeth(deskWoodType , cost, numberOfDrawers);

       }//end main

       private static void drawersMeth(int numberOfDrawers)

       {

           int numOfDrawers;

           Console.WriteLine("Enter the number of desk drawers");

           numOfDrawers = Convert.ToInt16(Console.ReadLine());

           numberOfDrawers = numOfDrawers;

       }//end drawersMeth

       private static string woodTypeMeth(string deskWoodType)

       {

           Console.WriteLine("Enter the desk wood type. (eg. type mahogany, oak, or pine)");

           deskWoodType = Convert.ToString(Console.ReadLine());

           switch (deskWoodType)

           {

               case "mahogany":

                   {

                       deskWoodType = "m";

                       break;

                   }

               case "oak":

                   {

                       deskWoodType = "o";

                       break;

                   }

               case "pine":

                   {

                       deskWoodType = "p";

                       break;

                   }

               default:

                   {

                       deskWoodType = "error";

                       break;

                   }

           }

           return deskWoodType;

       }// end woodTypeMeth

       private static int CalculateCostMeth(string deskWoodType, int numberOfDrawers, int cost)

       {

           int pine = 100;

           int oak = 140;

           int other = 180;

           int surchage = 30;

           if (deskWoodType == "p")

               cost = surchage + (numberOfDrawers *pine );

           else if (deskWoodType == "o")

               cost = surchage + (numberOfDrawers *oak );

           else

               cost = surchage + (numberOfDrawers *other );

           return cost;

       }// end CalculateCostMeth

       private static void OutPutCostMeth(int numberOfDrawers, string deskWoodType, int cost)

       {

           double totalCost = cost;

           Console.WriteLine("The number of drawers is {0}", numberOfDrawers);

           Console.WriteLine("The wood finish you have selected is ", deskWoodType);

           Console.WriteLine("The total cost is {0}", totalCost);

       }//end outputCost

   }//end class

}//end nameSpace

5 0
3 years ago
6. Which is not considered a storage device a. USB Flash Drive b. External hard Drive c. MS-Windows d. Internal Hard Drive e. Me
Lana71 [14]

Answer:

MS-Windows

Explanation:

MS-Windows is an operating system not a storage device.

6 0
3 years ago
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