Answer:
A
Explanation:
Option A is not true because a Boolean variable type can hold one of two values only that is (true/True or false/False).
All the other options given in the question are correct because
- A variable declaration refers to specifying its type and name
- If string variables are assigned a numeric values which is legal provided the values are enclosed in quaotes( " "), trying to carryout a mathematical operation like addition will result in string concatenation.
- The Variable name I_Love_to_eat_pizza is legal because it contains no special characters, doesn't start with a number and its not a reserved word in any language
Answer:
The expression on line 9 required 2 brackets
Explanation:
Given
The attached code
Required
Why syntax error.
The error points to line 10, but the error is actually from line 9
To get an integer input, the syntax is:
variable-name = int(input("Prompt"))
From the attached code, the line 9 is:
amount = int(input("Enter cheese order weight: ")
By comparing the syntax to the actual code on line 9, only 1 of the brackets is closed.
<em>This, in Python 3 is a sytax error</em>
Answer:
The answer is "The global Address List (GAL) is publishes in the new certificates".
Explanation:
Describe the GAL with relate to smart card:
- The GAL is a part of the outlook, that allows the users to make a group of mutual contacts and resources specified for your G Suite domain and searchable directory.
- It provides the main mail app, that offers you to make global contacts, and also provides basic contact, with the use of business shares global addresses with others. In this process, the co-worker can change their smart card.
Answer:
#include <bits/stdc++.h>
using namespace std;
bool isPalindrome(string str)
{
char a,b;
int length = str.length();
for (int i = 0; i < length / 2; i++)
{
a=tolower(str[i]);//Converting both first characters to lowercase..
b=tolower(str[length-1-i]);
if (b != a )
return false;
}
return true;
}
int main() {
string t1;
cin>>t1;
if(isPalindrome(t1))
cout<<"The string is Palindrome"<<endl;
else
cout<<"The string is not Palindrome"<<endl;
return 0;
}
Output:-
Enter the string
madam
The string is Palindrome
Enter the string
abba
The string is Palindrome
Enter the string
22
The string is Palindrome
Enter the string
67876
The string is Palindrome
Enter the string
444244
The string is not Palindrome
Explanation:
To ignore the cases of uppercase and lower case i have converted every character to lowercase then checking each character.You can convert to uppercase also that will also work.