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Novay_Z [31]
3 years ago
12

A grocery store sells a bag of 3 oranges for $2.79. How much would it cost for 4 oranges?

Mathematics
2 answers:
user100 [1]3 years ago
4 0
Divide 2.79 by 3 and you get 0.93 then times that by 4 you get your answer = 3.72
Kaylis [27]3 years ago
3 0

Answer:

$3.72

Step-by-step explanation:

Divide $2.79 by 3

$0.93 is the price of one orange

$0.93 times 4 is $3.72

Hope this helps!

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The product of 8 and a number algebraic expression
dybincka [34]

Answer: 8x

Step-by-step explanation:

Product stands for multiplication, so we need to use (×)

Let x = the number.

----------------------------------------------

The product of 8 and a number

8 × x=8x

3 0
3 years ago
Read 2 more answers
(Picture) MULTIPLYING POLYNOMIALS AND SIMPLIFYING EXPRESSIONS PLEASE HELP!!!!
kvv77 [185]

Answer:

Answer: Third option is the right answer.

Step-by-step explanation:

First we the write the expression

(a+b)(a^{2}+b^{2}-ab)

Now teacher says that the product of these polynomials will result in the sum of  a^{3}+b^{3}

Now the teacher ask if we put the value of a = 2x and b = 1 then what will be the expression look like.

(2x+1)\left [ (2x)^{2}+(1^{2})-(2x)(1)\right ]

=(2x+1)(4x^{2}+1-2x)

So third option is looking like our expression.

3 0
3 years ago
WILL MARK U AS BRAINLIEST!!! Evaluate the following expressions given the functions below:
Scorpion4ik [409]

sorry that was a mistake tee hee

7 0
3 years ago
9(2.3n+6)+10.45>43.7
kifflom [539]

Answer:

Step-by-step explanation:

9(2.3n+6)+10.45>43.7

(9*2.3n)+(9*6)+10.45>43.7

20.7n+54+10.45>43.7

20.7n+64.45>43.7

7 0
3 years ago
If a polynomial has one root in the form a+√b , it has a second root in the form of a_√b
gulaghasi [49]
When roots of polynomials occur in radical form, they occur as two conjugates.
That is,
The conjugate of (a + √b) is (a - √b) and vice versa.
To show that the given conjugates come from a polynomial, we should create the polynomial from the given factors.

The first factor is x - (a + √b).
The second factor is x - (a - √b).

The polynomial is
f(x) = [x - (a + √b)]*[x - (a - √b)]
      = x² - x(a - √b) - x(a + √b) + (a + √b)(a - √b)
      = x² - 2ax + x√b - x√b + a² - b
      = x² - 2ax + a² - b

This is a quadratic polynomial, as expected.

If you solve the quadratic equation x² - 2ax + a² - b = 0 with the quadratic formula, it should yield the pair of conjugate radical roots.
x = (1/2) [ 2a +/- √(4a² - 4(a² - b)]
   = a +/- (1/2)*√(4b)
   = a +/- √b
x = a + √b, or x = a - √b, as expected.
3 0
3 years ago
Read 2 more answers
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