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Answer:
1). a = 9.42 m
2). b = 6.37 m
3). c = 4.48 m
Step-by-step explanation:
In the figure attached,
By applying tangent rule in triangle ADE,
tan47 = 
c = 
c = 
c = 4.476
c ≈ 4.48 m
Now we apply the same rule in triangle ACE,
tan37° = 
b = 
b = 
b = 6.37 m
Now apply the tangent in triangle ABE,
tan27° = 
a = 
a = 
a = 9.42 m
Maria isn't correct of this. Adding these will get you 82960 (You add the numbers) She must have miscalculated.
Answer:
x>
−2
3
Step-by-step explanation:
see the attached figure to better understand the problem
we have that

Step 1
<u>Find the value of AC</u>
we know that
in the right triangle ABC

substitute the values in the formula

Step 2
<u>Find the value of BC</u>
we know that
in the right triangle ABC
Applying the Pythagorean Theorem

substitute the values

Step 3
<u>Find the value of BD</u>
we know that
in the right triangle BCD
Applying the Pythagorean Theorem

substitute the values


therefore
<u>the answer is</u>
the length of BD is 11.93 units