The number of $1, $5 and $10 are 49, 44 and 22 respectively.
<h3>How to use equation to find the number of bills?</h3>
There are 3 denominations of bills in a wallet: $1, $5, and $10.
There are 5 fewer $5-bills than $1-bills.
let
x = number of $1 bills
Hence,
number of $5 bills = x - 5
There are half as many $10-bills as $5-bills.
number of $10 bills = 1 / 2 (x - 5)
Therefore,
x + x - 5 + 1 / 2 (x - 5) = 115
2x - 5 + 1 / 2 x - 5 / 2 = 115
2x + 1 / 2 x - 5 - 5 / 2 = 115
5 / 2 x - 7.5 = 115
2.5x = 115 + 7.5
x = 122.5 / 2.5
x = 49
Number of $1 bills = 49
Number of $5 bills = 49 - 5 = 44
Number of $10 bills = 1 / 2 (49 - 5) = 22
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Answer:
(a) and (a)
Step-by-step explanation:
In both questions the denominator of the rational functions cannot be zero as this would make them undefined. Equating the denominators to zero and solving gives the values that x cannot be.
Given

solve (3 - x)(2 + x) = 0
Equate each factor to zero and solve for x
3 - x = 0 ⇒ x = 3
2 + x = 0 ⇒ x = - 2
x = 3 and x = - 2 are excluded values → (a)
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Given

solve
6x² + 10x - 4 = 0 ← in standard form
(x+ 2)(6x - 2) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
6x - 2 = 0 ⇒ 6x = 2 ⇒ x = 
x =
and x = - 2 are excluded values → (a)