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djverab [1.8K]
3 years ago
5

Two more than five times a number is less than or equal to 47

Mathematics
1 answer:
Sliva [168]3 years ago
7 0
5x + 2 < 47


Side note: put the line under the
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A number rounded to the nearest hundred thousand is 400,000.The same number rounded to the nearest ten thousand is 350,000.What
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340,000
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3 years ago
PLEASE I NEED THIS FAST there are 3 denominations of bills in a wallet: $1, $5, and $10. there are 5 fewer $5-bills than $1-bill
Natalija [7]

The number of $1, $5 and $10 are 49, 44 and 22 respectively.

<h3>How to use equation to find the number of bills?</h3>

There are 3 denominations of bills in a wallet: $1, $5, and $10.

There are 5 fewer $5-bills than $1-bills.

let

x = number of $1 bills

Hence,

number of $5 bills = x - 5

There are half as many $10-bills as $5-bills.

number of $10 bills = 1 / 2 (x - 5)

Therefore,

x + x - 5 + 1 / 2 (x - 5) = 115

2x - 5  + 1 / 2 x - 5 / 2 = 115

2x + 1 / 2 x - 5 - 5 / 2 = 115

5 / 2 x  - 7.5 = 115

2.5x  = 115 + 7.5

x = 122.5 / 2.5

x = 49

Number of $1 bills = 49

Number of $5 bills = 49 - 5 = 44

Number of $10 bills = 1 / 2 (49 - 5) = 22

learn more on equation here: brainly.com/question/13992796

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7 0
2 years ago
What is Melissa’s original salary if she gets 4% increase in pay and is now getting $29,12? Round to the nearest dollar.
andre [41]

Answer:

2

Step-by-step explanation:

7 0
3 years ago
Simplify the expression by combining like terms.
ollegr [7]

Answer:

Hi... Your answer is

-22d+f

4 0
3 years ago
Read 2 more answers
Please help ASAP. The question is down below.
erastovalidia [21]

Answer:

(a) and (a)

Step-by-step explanation:

In both questions the denominator of the rational functions cannot be zero as this would make them undefined. Equating the denominators to zero and solving gives the values that x cannot be.

Given

\frac{x-3}{(3-x)(2+x)}

solve (3 - x)(2 + x) = 0

Equate each factor to zero and solve for x

3 - x = 0 ⇒ x = 3

2 + x = 0 ⇒ x = - 2

x = 3 and x = - 2 are excluded values → (a)

------------------------------------------------------------------------

Given

\frac{-9x+3}{6x^2+10x-4}

solve

6x² + 10x - 4 = 0 ← in standard form

(x+ 2)(6x - 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

6x - 2 = 0 ⇒ 6x = 2 ⇒ x = \frac{1}{3}

x = \frac{1}{3} and x = - 2 are excluded values → (a)

7 0
3 years ago
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