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3 years ago

Another friend, with a mass of 75 kg, wants a push on the swing. How much force will

Mathematics

1 answer:

NeX [460]3 years ago

6 0

Answer:

735N

Step-by-step explanation:

According to Newton's second law;

Force = mass * acceleration due to gravity

Given

Mass = 75kg

Acceleration = 9.8m/s^2

Substitute into the formula;

F = 75 * 9.8

F = 735N

Hence the force required is 735N

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Could you help me please?

Nadya [2.5K]

--------------------------------------------------------------
Find x :
--------------------------------------------------------------
Sum of adjacent angles on a straight line is 180.

∠ABY + ∠YBC = 180
x + 25 + 2x + 50 = 180
3x + 75 = 180
3x = 105
x = 35

--------------------------------------------------------------
Check if AC is parallel to DF :
--------------------------------------------------------------
If AC is parallel to DF,
∠YBC = ∠BEF (Corresponding angles)

∠YBC = 2x + 50 = 2(35) + 50 = 120
∠BEF = 5x - 55 = 5(35) - 55 = 120

Since ∠YBC = ∠BEF, AC and DF are parallel.

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Answer: Since ∠YBC = ∠BEF, AC and DF are parallel.
---------------------------------------------------------------------------------------------

8 0

3 years ago

Read 2 more answers

If K is the midpoint of JL , JK = 6x + 11 and KL = 16x +1, find JL.<br> Pls I need help

Korvikt [17]

Since K is the midpoint of JL and we know that JK and KL are separate segments of JL, JK and KL are equal to each other.

6x + 11 = 16x + 1

Subtract 6x and 1 from both sides

10 = 10x

Divide both sides by 10

1 = x

We also know that:

JL = JK + KL = 6(1) + 11 + 16(1) + 1 = 6 + 11 + 16 + 1 = 34

3 0

3 years ago

A 12 foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away from the

ira [324]

Using Pythagoras theorem, the top of the ladder moving down when the foot of the ladder is 3 feet from the wall is of -0.518 feet/sec.

Let distance from the wall to the foot of the ladder is 'x' feet and the height of the top of the ladder is 'y' feet.

Pythagoras theorem, $x^{2} + y^{2} = (12)^{2}$ --->(1)

Given, $\frac{dx}{dt}= 2feet/second$ at x=3

Put x=3 in Pythagoras theorem equation (1)

$(3)^{2} + y^{2} = 144$

$y^{2} = 144 - 9$

$y^{2}$ = 135

y = 11.61

Derive equation (1) w.r.t to 't'

$2x\frac{dx}{dt} + 2y\frac{dy}{dt} = 0$ ---->(2)

substitute the value of 'x', 'dx/dt' and 'y' in equation (2), we get the fast of the top of the ladder moving down when the foot of the ladder is 3 feet from the wall

$2(3)(2) + 2 (11.61)\frac{dy}{dt} = 0$

12 + 23.22 $\frac{dy}{dt}$ = 0

$\frac{dy}{dt}= \frac{-12}{23.22}$

$\frac{dy}{dt} = -0.518$

Hence, using Pythagoras theorem the top of the ladder moving down when the foot of the ladder is 3 feet from the wall is of -0.518 feet/sec.

Learn more about Pythagoras theorem here

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5 0

2 years ago

What does the point (8,4) indicate in the terms of the context?

vredina [299]

8 milk cartons for 4 dollars? im sorry if im wrong

7 0

3 years ago

Justin is on a road trip. Over the past two days, he’s driven a total distance of 504 miles at an average speed of 56 miles/hour

irakobra [83]

Recall d = rt, distance = rate * time.

now, he has a speed rate of 56 mph for a distance of 504

$\bf d=rt\implies 504=56t\implies \cfrac{504}{56}=t\implies \stackrel{hours}{9}=t$

so, at that speed the whole driving time is 9 hours then. Ok, he drove 2 hours today, that means he drove 7 yesterday, 9 - 2.

how many miles is it for 7 hours at 56mph? d = rt ---> d = 56 * 7

that many miles he drove yesterday.

8 0

3 years ago