Another friend, with a mass of 75 kg, wants a push on the swing. How much force will
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Answer:
A sample size of 79 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
For this problem, we have that:
The margin of error is:
95% confidence level
So , z is the value of Z that has a pvalue of
, so
.
What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.09?
A sample size of n is needed.
n is found when M = 0.09. So
Rounding up to the nearest whole number.
A sample size of 79 is needed.
Answer:
(A) There should have been 5 outcomes of HT
(B) The experimental probability is greater than the theoretical probability of HT.
Step-by-step explanation:
Given
-- Sample Space
--- Sample Size
Solving (a); theoretical outcome of HT in 20 tosses
First, calculate the theoretical probability of HT
Multiply this by the number of tosses
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Solving (b); experimental probability of HT
Here, we make use of the table
---- Experimental Probability
In (a), the theoretical probability is:
---- Experimental Probability
By comparison;