4250*.07*1.5=446.25
4250-446.25=3803.75
3803.75/4250= .89
That is all that i could get out of what you provided
Answer:
0.25
Step-by-step explanation:
We have a total of ten student, and three students are randomly selected (without replacement) to participate in a survey. So, the total number of subsets of size 3 is given by 10C3=120.
On the other hand A=Exactly 1 of the three selected is a freshman. We have that three students are freshman in the classroom, we can form 3C1 different subsets of size 1 with the three freshman; besides B=Exactly 2 of the three selected are juniors, and five are juniors in the classroom. We can form 5C2 different subsets of size 2 with the five juniors. By the multiplication rule the number of different subsets of size 3 with exactly 1 freshman and 2 juniors is given by
(3C1)(5C2)=(3)(10)=30 and
Pr(A∩B)=30/120=0.25
Answer:
follows are the solution to this question:
Step-by-step explanation:
Please find the correct question in the attached file:
The formula for calculating the Confidence interval of proportion:


The number of learners with access to working at home on a computer:

Lower limit =0.48
upper limit = 0.60


Answer:
6- Part A: 
Part B: 
Solution of the system: 
Step-by-step explanation:
<u>Part A:</u>
In words, the equation is formed like this:
Total kg of Arabica + Total kg of Robusta = Total kg of coffee
Now, the total of each yield is calculated by the product of kg/hectare and number of hectares. Thus, the equation is:

<u>Part B:</u>
In words:
Arabica's worth + Robusta's worth = plantation worth
Each yield's worth is given by the product of the price per kg and the corresponding production. So, the equation is:

2+2 = 4. Bro it was so hard. Did i helped you?