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maw [93]
3 years ago
13

Which of the following expressions is equivalent to the expression below? 1.06(x - 0.3x)

Mathematics
2 answers:
Llana [10]3 years ago
5 0

Answer:

0.742x

Step-by-step explanation:

you have to distribute the number outside the parenthesis into the parenthesis

you get 1.06x-0.318x which would equal 0.742x.

cricket20 [7]3 years ago
3 0

Answer:

0.742x

Step-by-step explanation:

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20 points! Thank you
julsineya [31]
HEY THERE !!

Factorization of the trinomial
3x^3 +6x^2 -24x
will be :-

taking common 3x

=>3x(x^2+2x-12)......1️⃣

now the factorization of (x^2+2x-12) will be
(x-2)(x+4).......2️⃣

so your answer from 1️⃣and 2️⃣ is (A) 3x(x-2)(x+4).

Hope it helped you.
3 0
3 years ago
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PLEASE HELP!! Evaluate the expression below using the properties of operations. Show all work.
VikaD [51]

Answer:

The answer I believe is -185 1/7

Step-by-step explanation:

I followed PEMDAS.

5 0
2 years ago
Read 2 more answers
Can someone help will give brainliest
Sonbull [250]

Answer:

Looking at this, slope seems to be 2 for the graph

So, looking at your options, -4 is less than 2, therefore, the answer is

D, with slope -4

6 0
3 years ago
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Please help me it is due tomorrow
larisa86 [58]
It should be H.13, sorry if this not 100% correct
7 0
3 years ago
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Explain how to find each root, with its multiplicity, for the polynomial y=x^5-27x^2.
Nuetrik [128]

The roots of y = x^{5}-27\cdot x^{2} are 0 (multiplicity 2), -3 (multiplicity 1), -\frac{3}{2}+i\,\frac{3\sqrt{3}}{2} (multiplicity 1) and -\frac{3}{2}-i\,\frac{3\sqrt{3}}{2} (multiplicity 1).

The characteristics of the polynomial can be derived from algebraic techniques. Roots and multiplicity can be found by <em>factoring</em> the polynomial. The multiplicity is represented by a power binomial of the form:

(x-r_{i})^{m},\,m \le n (1)

Where n is the grade of the polynomial.

Now we proceed to factor the formula:

y = x^{5}-27\cdot x^{2}

y = x^{2}\cdot (x^{3}-27)

y = x^{2}\cdot (x^{2}+3\cdot x +9)\cdot (x-3)

Please notice that x^{2}+3\cdot x + 9 have two complex roots.

y = x^{2}\cdot \left(x+\frac{3}{2}-i\,\frac{3\sqrt{3}}{2}  \right)\cdot \left(x+\frac{3}{2}+i\,\frac{3\sqrt{3}}{3}  \right)\cdot (x-3)

The roots of y = x^{5}-27\cdot x^{2} are 0 (multiplicity 2), -3 (multiplicity 1), -\frac{3}{2}+i\,\frac{3\sqrt{3}}{2} (multiplicity 1) and -\frac{3}{2}-i\,\frac{3\sqrt{3}}{2} (multiplicity 1).

We kindly invite to see this question on polynomials: brainly.com/question/1218505

7 0
2 years ago
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