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Sunny_sXe [5.5K]
3 years ago
6

Help me pleaseeeeeeeeeeeeee

Mathematics
1 answer:
lubasha [3.4K]3 years ago
6 0
I had this and it was b for me
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What is a factor that is less than 1?
solong [7]

Answer:

none

Step-by-step explanation:

6 0
3 years ago
Angie and Becky each completed a separate proof to show that the measures of vertical angles AKG and HKB are equal. Who complete
Ann [662]

Answer:

Becky completed the proof incorrectly.

Step-by-step explanation:

The only difference of the two proofs, at least what I can see, is the reason for step 2. Angie claims that it is the Definition of Supplementary Angles, while Becky claims Angle Addition Postulate.

The Definition of Supplementary Angles states that m∠A + m∠B = 180°.

While the Angle Addition Postulate states that m∠A + m∠B = m∠C.

Because the context used is that  m∠AKG + m∠GKB = 180° and m∠GKB + m∠HKB = 180°, it would be using the Definition of Supplementary Angles.

So Becky is the one who is incorrect.

7 0
2 years ago
What is a standard transmission
saul85 [17]

Answer:

i would say B a stick shift

Step-by-step explanation:

8 0
3 years ago
An equilateral triangle with a side length of 6mm and a height of 5.2mm is divided vertically into halves. Find the area of one
Viefleur [7K]

There are two ways you could go about solving this.

You could divide the length of the base (6mm) by 2 and use that to find the area or you could find the area of the whole triangle using 6mm and divide that by 2.

I will use the first method I described:

base = 6/2

base = 3 mm

height = 5.2 mm

area = bh/2

area = (3 * 5.2)/2

area = 7.8 square mm

(don't forget your units)


Using the other method would look like this:

area = bh/2

b = 6

h = 5.2

area = (6 * 5.2)/2

area = 15.6 square mm

area/2 = 7.8 square mm


As you can see either method yields the same result.

Hope this helped.

Cheers and good luck,

Brian

8 0
3 years ago
Molecules of a toxic chemical eventually decompose into inert substances. Suppose the decomposition time is exponentially distri
koban [17]

Answer:

a) 4.16 years

b) 27.73 years

c) 238.44 years

d) 3,870.53 years

Step-by-step explanation:

Let X be the random variable that measures the decomposition time.

a)

\bf \lambda =6

In this case, since the decomposition time is exponentially distributed with a mean of 1/6, we have

\bf P(X\leq t)=1-e^{-t/6}\Rightarrow P(X>t)=1-(1-e^{-t/6})=e^{-t/6}

and we must find a t such that P(x>t)=0.5.

\bf P(X>t)=0.5\Rightarrow e^{-t/6}=0.5\Rightarrow -t/6=ln(0.5)\Rightarrow t=-6ln(0.5)=4.16\;years

b)

\bf \lambda =40

\bf P(X>t)=0.5\Rightarrow e^{-t/40}=0.5\Rightarrow -t/40=ln(0.5)\Rightarrow t=-40ln(0.5)=27.73\;years

c)

\bf \lambda =344

\bf P(X>t)=0.5\Rightarrow e^{-t/344}=0.5\Rightarrow -t/344=ln(0.5)\Rightarrow t=-344ln(0.5)=238.44\;years

d)

\bf \lambda =5584

\bf P(X>t)=0.5\Rightarrow e^{-t/5584}=0.5\Rightarrow -t/5584=ln(0.5)\Rightarrow t=-5584ln(0.5)=3870.53\;years

5 0
3 years ago
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