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4 years ago

5

How do you do unto rate?

1 answer:

Margarita [4]4 years ago

4 0

If you mean unit rate you find it by dividing the top number by the bottom number to fin the singular number or unit rate.

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Determine whether the number 1 is prime or composite. Explain how you know.

nikdorinn [45]

To determine if a number is prime or composite, follow these steps: Find all factors of the number. If the number has only two factors, 1 and itself, then it is prime. If the number has more than two factors, then it is composite.

From Google.

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3 years ago

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Evaluate.<br><br> 32−[(4+2×3)×2]<br><br> Thk u!

gulaghasi [49]

Answer:

$here \: w e \: can \: use \: bodmas \\ 32 - ((4 + 2 \times 3) \times 2) \\ = 32 - (4 + 6) \times 2) \\ = 32 - 10 \times 2 \\ = 32 - 20 \\ = 12 \\ thank \: yuou$

7 0

3 years ago

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Wyatt hiked 6 miles in 2 hours . At this same rate , what is the total number of miles Wyatt could hike in 9 hours

Lelechka [254]

Answer:

27

Step-by-step explanation:

He walked 3 miles an hour. So to find howmany miles he walked in nine hours you would do this: 3x9=27

5 0

3 years ago

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Jim deposited $350 into a savings account with simple interest at Hunting Bank. He left the money in his account with no changes

padilas [110]

Answer:

2.321428571%

Step-by-step explanation:

Given in the question,

P=$350

T=4years

I=$32.50

We know that

I=PTR/100

32.50=350*4*R/100

R=32.50*100/350*4

R=2.321428571%

So, the rate of interest is 2.321428571%

4 0

4 years ago

Find the maximum and minimum values of the function f(x,y)=2x2+3y2−4x−5 on the domain x2+y2≤100. The maximum value of f(x,y) is:

ryzh [129]

First find the critical points of <em>f</em> :

$f(x,y)=2x^2+3y^2-4x-5=2(x-1)^2+3y^2-7$

$\dfrac{\partial f}{\partial x}=2(x-1)=0\implies x=1$

$\dfrac{\partial f}{\partial y}=6y=0\implies y=0$

so the point (1, 0) is the only critical point, at which we have

$f(1,0)=-7$

Next check for critical points along the boundary, which can be found by converting to polar coordinates:

$f(x,y)=f(10\cos t,10\sin t)=g(t)=295-40\cos t-100\cos^2t$

Find the critical points of <em>g</em> :

$\dfrac{\mathrm dg}{\mathrm dt}=40\sin t+200\sin t\cos t=40\sin t(1+5\cos t)=0$

$\implies\sin t=0\text{ OR }1+5\cos t=0$

$\implies t=n\pi\text{ OR }t=\cos^{-1}\left(-\dfrac15\right)+2n\pi\text{ OR }t=-\cos^{-1}\left(-\dfrac15\right)+2n\pi$

where <em>n</em> is any integer. We get 4 critical points in the interval [0, 2π) at

$t=0\implies f(10,0)=155$

$t=\cos^{-1}\left(-\dfrac15\right)\implies f(-2,4\sqrt6)=299$

$t=\pi\implies f(-10,0)=235$

$t=2\pi-\cos^{-1}\left(-\dfrac15\right)\implies f(-2,-4\sqrt6)=299$

So <em>f</em> has a minimum of -7 and a maximum of 299.

4 0

3 years ago