K’ (-3,-3)
L’(1,-1)
M’(-1,-5)
N’(-5,-7)
D’(0,4)
E’(4,3)
F’(2,-5)
G’(-2,-4)
The horse traveled 439.6 feet after walking around the track 5 times
<u><em>Solution:</em></u>
Given that, horse walks around a circular track while its trainer stands in the center
The trainer is 14 feet from the horse at all times
Therefore, radius of circular track = 14 feet
The circumference of circle is the distance traveled by horse for 1 lap
<em><u>The circumference of circle is given as:</u></em>

Where, "r" is the radius and
is a constant equal to 3.14

Thus the distance traveled by horse for one time in circular track is 87.92 feet
<em><u>About how far had the horse traveled after walking around the track 5 times? </u></em>
Multiply the circumference by 5

Thus the horse traveled 439.6 feet after walking around the track 5 times
Answer:
it is 2
Step-by-step explanation:
Answer:
Image point → (-4, 0)
Step-by-step explanation:
Coordinate of a point → (0, 1)
Rule for the transformation has been given as,
D₄ o R₉₀
First use R₉₀ → Rotation of the point by 90° counterclockwise
Rule for the rotation of a point (x, y) by 90° counterclockwise about the origin,
(x, y) → (-y, x)
(0, 1) → (-1, 0)
Further use D₄ → Dilation of the point by a scale factor of 4 about the origin
If a point (x, y) is dilated by a scale factor 'k' about the origin rule for the dilation is,
(x, y) → (kx, ky)
By applying this rule,
(-1, 0) → (-4, 0)
Therefore, image point will be → (-4, 0)