Solving for x
Since x<span> is on the right hand side of the </span>equation<span> switch the sides so it is on the left hand side of the </span>equation<span>.
</span><span>2x+yi=−14−3i
</span>
Since <span>yi</span><span> does not contain the </span>variable<span> to solve for move it to the right-hand side of the </span>equation<span> by subtracting </span><span>yi</span><span> from both sides.
</span><span>2x=−yi−14−3i
</span>Divide<span> each </span>term<span> in the </span>equation<span> by </span><span>2.
</span><span>x=−<span><span>yi/</span>2</span>−7−<span><span>3i/</span>2
Solving for y
</span></span>Since y<span> is on the right hand side of the </span>equation<span> switch the sides so it is on the left hand side of the </span>equation<span>.
</span><span>2x+yi=−14−3i
</span>Since <span>2x</span><span> does not contain the </span>variable<span> to solve for move it to the right hand side of the </span>equation<span> by subtracting </span><span>2x</span><span> from both sides.
</span><span>yi=−2x−14−3i
</span>Divide<span> each </span>term<span> in the </span>equation<span> by </span><span>i.
</span><span>y=2xi+14i−3
</span>x=−yi/2−7−3i/2
y=2xi+14i−3
S casts a "shadow" on the x-y plane given by the set
Each cross section is a square whose side length is determined by the vertical distance between y = 1 and y = x², which is |1 - x²|. But since -1 ≤ x ≤ 1, this distance simplifies to 1 - x².
The volume of an infinitesimally thin section is then (1 - x²)² ∆x (where ∆x represents its thickness), and so the volume of S is
The integrand is even, so this integral is equal to twice the integral over [0, 1] :
Answer:
Step-by-step explanation:
The equation of a circle is written with the center and radius into the vertex form 
.
Here h = -2 and k = 1. Substitute these values with r = 3.
The answer would be c but why u have d
Answer:
Step-by-step explanation:
The formula of a surface area of a cylinder:
r - radius
H - height
We have r = 40mm and H = 50mm. Substitute:
