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2 years ago

Explain box and whisker and how does it work?

Mathematics

1 answer:

bezimeni [28]2 years ago

4 0

a box plot is a graph that summarizes numerical data based on quartiles, which divide a data set into fourths

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5) Bianca bought a baseplate of 12 inches length and 10 inches width. Find the area on

shepuryov [24]

Answer:

The area of the base plate is 120 in

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Which is the solution set of the inequality 15y-9<36

m_a_m_a [10]

15y - 9 <36.
Add 9 to each side.

15y- 9 (+9) < 36 + 9.
15y < 45.
y < 3.
Hope it helps! :)

7 0

3 years ago

Read 2 more answers

A pilot has just started on the glide path for landing at an airport with a runway of length 9000 feet. The angles of depression

ki77a [65]

Answer:

a. See attachments

B. 163630.2ft

C. 147056.70ft

D. 49205.4ft

Step-by-step explanation:

Check attachments for details

Angle a.. Angle of dep to beginning of runway

Angle b... Angle of del to end of runway

AD... Altitude of plane

DB..... Ground distance before touch down

AC... Air distance travelled until touch down on the near end of runway

5 0

3 years ago

A rectangle has a height to width ratio of 3:4.5. Give two examples of dimensions for rectangles that could be scaled versions o

OlgaM077 [116]

We have been given that a rectangle has a height to width ratio of 3:4.5.

Let h be height and w be width of rectangle.

We can set our given information in an equation as:

$\frac{h}{w} =\frac{3}{4.5}$

$h=\frac{3}{4.5} *w$

Now we will substitute h=1 in this equation.

$1=\frac{3}{4.5} *w$

$3w=4.5$

$w=\frac{4.5}{3} =1.5$

We can see that width of rectangle is 1.5 times height of rectangle.

Our one set of dimensions of rectangle will be: height=1 and width=1.5.

We can get many set of dimensions for our rectangle by multiplying both height and width of rectangle by same number.

Multiplying by 5 we will get our dimensions as: height 5 and width 7.5.

Therefore, (1 and 1.5) and (5 and 7.5) dimensions for rectangle will be scaled version of our rectangle.

6 0

2 years ago

If a+b+c=16 and a^2+b^2+c^2=90 then find the value a^3+b^3+c^3-3abc

grin007 [14]

$(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)\\(16)^2=90+2(ab+bc+ca)\\256-90=2(ab+bc+ca)\\166/2=ab+bc+ca\\83=ab+bc+ca\\a^3-b^3-c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)\\(a+b+c)(a^2+b^2+c^2-(ab+bc+ca))\\16(90-(83))\\16(7)\\=112$

3 0

2 years ago