3 years ago

Find the values of x and y

Mathematics

2 answers:

STALIN [3.7K]3 years ago

6 0

Answer:

x = 90

y = 44

is the answer for the question

sukhopar [10]3 years ago

4 0

Option 2 is right. I did the work and got that. Please give me the red heart! Merry Christmas

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vfiekz [6]

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$- 13.8 + 1.3 = \frac{u}{5}$

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3 years ago

A regular triangular pyramid has a base area of 31.5 mm2

Yuri [45]

Answer:

maybe do the math

Step-by-step explanation:

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olga55 [171]

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3 years ago

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Bogdan [553]

Answer:

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3 years ago

Lim x-1 x³-2x²+3x-2/(2x^4-3x+1)

UkoKoshka [18]

Since the limit becomes the undetermined form

$\displaystyle \lim_{x\to 1} \dfrac{x^3-2x^2+3x-2}{2x^4-3x+1} \to \dfrac{0}{0}$

it means that both polynomials have a root at $x=1$ . So, we can fact both numerator and denominator:

$x^3-2x^2+3x-2 = (x-1)(x^2-x+2)$

$2x^4-3x+1 = (x-1)(2x^3+2x^2+2x-1)$

So, the fraction becomes

$\dfrac{(x-1)(x^2-x+2)}{(x-1)(2x^3+2x^2+2x-1)} = \dfrac{x^2-x+2}{2x^3+2x^2+2x-1}$

Now, as x approaches 1, you have no problems anymore:

$\displaystyle \lim_{x\to 1} \dfrac{x^2-x+2}{2x^3+2x^2+2x-1} \to \dfrac{2}{5}$

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3 years ago