We know that
circumference=2*pi*r-------> r=circumference/(2*pi)
circumference=30 in
r=circumference/(2*pi)------> 30/(2*pi)-----> 4.7746 in
the radius of a <span>standard basketball is 4.77 in
</span>
<span>the distance between the ball and the rim is equal to
</span>radius of a basketball rim minus radius of a a standard basketball
radius of a basketball rim =18/2------> 9 in
radius of a a standard basketball=4.77 in<span>
</span>
the distance between the ball and the rim=[9-4.77]------> 4.23 in
the answer is
4.23 in
4pm because it takes them 3 hours to get set and sunset is at 7pm so 7-3=4pm boom!
Answer:
The roots are real and distinct.
Step-by-step explanation:
Given the following equation:
In this problem, a = 1, b = k and c = -k - 2
The discriminant is b² - 4ac, and for the roots to be real and distinct, it must be at least or greater than 0.
We get,
(k)²- 4(1)(-k - 2) = 1 - 4(-k - 2)
= k² + 4k + 8
Let's check:
At k = -2,
At k = 0,
At k = -100,
Therefore, we can conclude that for all values of k, the roots are real and distinct.
This has been a long way in answering this question, so it would be great if you could mark me as brainliest
Answer:
7238.2
Step-by-step explanation:
V = 
= 7238.2
C= 2(3.14)r or 3.14D
so, if the diameter (d) is given just multiply it by 3.14. If the radius (r) is given multiply it by 2 then multiply that answer by 3.14 (or just multiply the radius by 6.28)
Pay attention to the units, then find the answer at the bottom.
