Answer:
A) attached below
B) 0.61
C) 0.47
Step-by-step explanation:
Given data:
Total number of lizards infected = 38
Of the 15 species B lizards 40% survived
For specie C one more survived than died
Out of the 24 lizards that died 1/3 were species A
<u>A) contingency table </u>
attached below
<u>B) Determine the proportion of these lizards in this study that were either specie A or Specie B </u>
P ( A or B ) = ( 8 + 15 ) / 38 = 0.605 ≈ 0.61
<u>C) determine the probability that specie C lizard did not study </u>
P ( not surviving | C ) = 7 / 15 = 0.466 ≈ 0.47
Answer:
Substitute n =1, 2, 3, 4, 5 to get the first five terms.
Step-by-step explanation:
(4). 
To find the first term, substitute n = 1.
Therefore,
= 2
= 6
= 18
= 54
= 168
Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.
(5). 
= 4



Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.
There are 60 minutes in an hour and percent means per one hundred so:
p/100=18/60
p=1800/60
p=30%
Distribute ^4 to both 2 and q^5
2^4 = 2 x 2 x 2 x 2 = 16
(q^5)^4 = q^20
16(q^20) = 16q^20
16q^20 is your answer
hope this helps