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liberstina [14]

3 years ago

7

A club is selling hats and jackets as a fundraiser. They have to stay within a budget of $900. They can order up to 200 items. E

ach hat costs $3 and each jacket costs $4.

1 answer:

Law Incorporation [45]3 years ago

8 0

what's the question??

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Clem Colfax had $10 to buy groceries. He needed milk costing 70 cents a carton, bread costing 60 cents a loaf, breakfast cereal

zaharov [31]

Cost of milk per carton = $ 70 cents = 70/100 = $0.7
Cost of bread per loaf = $60 cents = 60/100 = $0.6
Cost of cereals per box = $50 cents = 50/100 = $0.5
Cost of meat per pound = $1.50

If x is the number of cartons of milk bought, then
Number of loafs = x/2
Number pf boxes of cereals = x/2 +1
Number of pounds of meat = x/2 +1

Therefore,
0.7*x + 0.6*x/2 + 0.5 (x/2+1) + 1.5 (x/2+1) = 10
0.7x + 0.3x + 0.25x + 0.5 + 0.75x + 1.5 = 10
2x + 2 =10
2x = 8
x = 4

Substituting;
Milk cartons = 4
Number of bread = 4/2 = 2
Boxes of cereals = 2+1 = 3
Pounds of meat = 3

8 0

2 years ago

What are the x-coordinates of the solutions to this system of equations?

Vikentia [17]

X equals 4 because 2 times 2 equals 4 and then 4 times 4 =16

6 0

2 years ago

Pls help me !!!!!!!!!!!!!!!!!!!!!!!!

Vikentia [17]

Answer:

9.89 m

Step-by-step explanation:

AC is the hypotenuse (H)

x is the opposite (O)

O and H are in sine

sin=O/H

H=O/sin

H=7.9/sin(53)

=9.89187169943418

3 SF

9.89 m

8 0

3 years ago

Read 2 more answers

An observer for a radar station is located at the origin of a coordinate system. Find the bearing of an airplane located at the

AfilCa [17]

Answer:

135 degrees

$S45^{0}E$

Step-by-step explanation

Consider the attached diagram

we are required to find the bearing of the aeroplane,

Consider the right angled triangle BOE

|OB|=4 unit

|AB|=4 Units

$Tan \alpha =\frac{Opposite}{Adjacent} =\frac{4}{4} \\\\\alpha=Tan^{-1} 1=45 degrees$

The Bearing of the Aeroplane is therefore given:

(i)From North Clockwise as: 90+45 =135 degrees

(ii)From a North South Line as $S45^{0}E$

6 0

2 years ago

Find the distance between the points (2, 7) and (-6, -2).

maw [93]

Answer:

Approximately 12.04 units.

Step-by-step explanation:

The find the distance between any two points, we can use the distance formula, which is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

We have the points (2,7) and (-6,-2). Let's let (2,7) be (x₁, y₁) and let's let (-6, -2) be (x₂, y₂). Substitute:

$d=\sqrt{(-6-2)^2+(-2-7)^2$

Subtract:

$d=\sqrt{(-8)^2+(-9)^2$

Square:

$d=\sqrt{64+81}$

Add:

$d=\sqrt{145}$

Approximate

$d=\sqrt{145}\approx12.04$

So, the distance between (2,7) and (-6,-2) is approximately 12.04 units.

And we're done!

7 0

3 years ago