Gemma was hiking for 2 1/2 a hour for 3 hours so u have to multiply 2.5 by 3 and that gonna equal 7.5 so u leave that alone and come back to it later so u get 11 3/8 minus 7.5 and it gonna equal 3 7/8 and I hope that helped you
Suppose the larger pump alone can empty the tank in L hours, and the smaller pump can finish the job in S hours, then each hour the large pump empties 1/L portion of the tank, and the small pump empties 1/S per hour
Working together for three hours, they empty the whole tank, which is 100% of it, so 3/L+3/S=100%=1
Larger pump can empty the tank in 4 hours less than the smaller one, so L=S-4
replace L: 3/(S-4)+3/S=1
Make the denominator the same to solve for:
3S/[S(S-4)] +3(S-4)/[S(S-4)]=1
(3S+3S-12)/[S(S-4)]=1
(3S+3S-12)=[S(S-4)]
S^2-10s+12=0
use the quadratic formula to solve for S
S is about 8.6
The answer is not whole hour.
Answer: 3/5
Step-by-step explanation: Just divide both by 5.
Answer:
D
Step-by-step explanation:
is the correct answer i believe.
This is easy. Select different values for x to find y values.
For example, let x = 0.
y = 8x + 12
y = 8(0) + 12
y = 0 + 12
y = 12
On your table, you have x = 0 and y = 12.
Do the same using other values of x.
