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IRISSAK [1]
3 years ago
13

Alexa is designing a paper airplane whose final shape, when viewed from the top or bottom, is a trapezoid. A sketch of her

Mathematics
1 answer:
Eduardwww [97]3 years ago
6 0

Answer:

2cm, 3 cm, 3cm

Step-by-step explanation:

the base is 2cm and its 3cm high

ps. if i dont get this right than dont send hate just say no thats not it

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MariettaO [177]

Answer:

I think its the second answer chose

Step-by-step explanation:

I hope this helps! Have a nice day! Owa Owa!

6 0
3 years ago
The diameter of a circle measures 32 yd. What is the circumference of the circle?
Alexxandr [17]

Answer:

100.48yds

Step-by-step explanation:

C= Circumference

π=3.14

R=radius

C=2πr

C=2(3.14)*16

C=6.28*16

C=100.48yds

4 0
3 years ago
The schools computer lab goes through 5 reams of printer paper every 2 weeks. Find out how long 6 cases of printer paper is like
hram777 [196]

number of reams= 6×8 =48

number of 2 weeks 48 reams can last= 48/5= 9.6

time 48 reams of paper can last= 9.6×2= 19.2 weeks

5 0
4 years ago
Joe earns $9 per hour. He worked x hours on both Wednesday and Friday, and 8 hours on both Tuesday and Saturday. Write an expres
Tamiku [17]

To find the total amount earned, you need to multiply the number of hours worked by the pay rate. Joe worked x hours for 2 days. That’s 2x hours. He worked 8 hours for 2 days. That’s 8(2), or 16 hours. The total number of hours he worked is 2x + 16. He gets paid $9/hour, so an expression for the total amount earned is 9(2x + 16), or 18x + 144.

8 0
4 years ago
Read 2 more answers
points C,D, and E are collinear on CE, and CD:DE = 3/5. C is located at (1,8), D is located at (4,5), and E is located at (x,y).
kap26 [50]

Answer:

The point E is located at (9,0)

x=9, y=0

Step-by-step explanation:

we have that

Points C,D, and E are collinear on CE

Point D is between point C and point E

we know that

CE=CD+DE -----> equation A (by addition segment postulate)

\frac{CD}{DE}=\frac{3}{5}

CD=\frac{3}{5}DE ------> equation B

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

<em>Find the distance CD   </em>

we have

C(1,8), D(4,5)

substitute in the formula

CD=\sqrt{(5-8)^{2}+(4-1)^{2}}

CD=\sqrt{(-3)^{2}+(3)^{2}}

CD=\sqrt{18}\ units

<em>Find the distance DE</em>

substitute the value of CD in the equation B and solve for DE

\sqrt{18}=\frac{3}{5}DE

DE=\frac{5\sqrt{18}}{3}\ units

<em>Find the distance CE</em>

CE=CD+DE

we have

DE=\frac{5\sqrt{18}}{3}\ units

CD=\sqrt{18}\ units

substitute the values in the equation A

CE=\sqrt{18}+\frac{5\sqrt{18}}{3}

CE=\frac{8\sqrt{18}}{3}

<em>Applying the formula of distance CE</em>

we have

CE=\frac{8\sqrt{18}}{3}

C(1,8), E(x,y)    

substitute in the formula of distance

\frac{8\sqrt{18}}{3}=\sqrt{(y-8)^{2}+(x-1)^{2}}

squared both sides

128=(y-8)^{2}+(x-1)^{2}  -----> equation C

<em>Applying the formula of distance DE</em>

we have

DE=\frac{5\sqrt{18}}{3}\ units

D(4,5), E(x,y)    

substitute in the formula of distance

\frac{5\sqrt{18}}{3}=\sqrt{(y-5)^{2}+(x-4)^{2}}

squared both sides

50=(y-5)^{2}+(x-4)^{2}  -----> equation D

we have the system

128=(y-8)^{2}+(x-1)^{2}  -----> equation C

50=(y-5)^{2}+(x-4)^{2}  -----> equation D

Solve the system by graphing

The intersection point both graphs is the solution of the system

The solution is the point (9,0)

therefore

The point E is located at (9,0)

see the attached figure to better understand the problem

6 0
3 years ago
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