Answer:it’s B on edge bro
Step-by-step explanation:
Mx - y
5 times 3 - 8
15 - 8
=
7
A=g≈-32
v=⌠a dt since a≈-32
v=-32t+C, where C is the initial velocity, which we are told is 20 ft/s
v=-32t+20
h=⌠v dt
h=-32t^2/2+20t+C, where C is the initial height, so what is a reasonable initial height? How about 3 ft since we are swinging a bat around maybe our waist level... maybe :P
h=-16t^2+20t+3
Your choices may have made a different assumption about the initial height of course but you did not show your choices, but certainly it will be:
h(t)=-16t^2+20t+hi, where hi is the initial height in feet.
This of course ignores air resistance and flight dynamics of a spinning ball with seams, which will make a significant difference in real life :)
Answer:
well if its 212 feet above the ground and cant incline more tjan 35 degrees it would be 46169?
Step-by-step explanation:
