Answer:
<em>1) the exact distance = 9.428571429 feet</em>
<em>the approximate distance = 9.4 feet</em>
<em></em>
<em>2) the exact area = 7.071428571 ft^2</em>
<em>the approximate area = 7 ft^2</em>
<em></em>
Step-by-step explanation:
Required diameter d = 3 feet
1) The distance around the outside of the pit is the circumference of the circle that will be formed by this circular fire pit.
circumference of a circle is given as = πd = 
x 3 = 9.428571429 feet
the exact distance = 9.428571429 feet
the approximate distance = 9.4 feet
2) The area of the circle that will be formed = 
= 
= 7.071428571 ft^2
the exact area = 7.071428571 ft^2
the approximate area = 7 ft^2
<span>3.00x10^8 meters.
If I'm reading this problem correctly, light is traveling at 9.45x10^15 meters per year and that there's 3.15x10^7 seconds per year. So you desire to know the speed of light in meters per second. This is mostly an exercise in handing scientific notion. So we need to divide the total distance that light traveled by the number of seconds. With scientific notation, you divide the significands and subtract the exponents to perform division. So
9.45 / 3.15 = 3 ; Dividing the significands
15 - 7 = 8 ; Subtracting the exponents.
So the answer is 3x10^8 meters per second.
Since our data has 3 significant figures, the result should also have 3 significant figures, so the final result is 3.00x10^8 meters.</span>
Answer:
one side of the equation is a quadratic equation, and the other side of the equation is a quadratic expression
Step-by-step explanation:
the description needs to be the same for each equation. For example linear and linear would work as well.
Answer:
3200
Step-by-step explanation:
area= (l*b)
area=(160*20)
area=3200
Answer:
-125
Step-by-step explanation:
[-5]^3 = -125
