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deff fn [24]
4 years ago
7

Leslie and Daniel plan to put an above-ground pool in the backyard of their new home. The backyard is rectangular, 30 feet by 50

feet, and the pool is circular, 24 feet in diameter and 4 1/3
feet tall.
Leslie and Daniel plan to plant grass in the rest of the yard. How much of the backyard, in square feet, is not covered by the pool? (Use 3.14 for π.)
Mathematics
1 answer:
Brut [27]4 years ago
4 0
1047.84ft² is not covered by the pool.
Find the area of the yard covered by pull using the area of a circle formula (the height is irrelevant in this case). If the diameter of the pool is 24 feet, its radius is 12 (half of the diameter)

A = 3.14r^2
A =3.14(144)
A = 452.16 ft²

Subtract the area of the pool from the area of the yard to get the area of the yard that is not covered by the pool. If the dimensions of the yard are 30ft by 50ft, you multiply them to get the area: 1500ft²

Total yard area: 1,500ft²
Area of yard without pool: 1,500ft² - 452.16ft² = 1047.84ft²
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irga5000 [103]

Answer:

-11, 723

Step-by-step explanation:

(27+15)/3+8(4+3-10)=-11

(90+30)*6-7*0+(10+5)/5=723

4 0
3 years ago
Kenneth signed up to receive Internet service for $13 per month plus a $30 start-up fee. Which equation could be used to find th
zimovet [89]

The equation 13x+30=134 can be used to find the number of months Kenneth can receive internet service.

Step-by-step explanation:

Given,

Start up fee to receive internet = $30

Per month charges = $13

Total amount = $134

Let,

x be the number of months.

y be the total cost.

y = 13x+30

Putting y=134

134=13x+30\\13x+30=134

The equation 13x+30=134 can be used to find the number of months Kenneth can receive internet service.

Keywords: equation, addition

Learn more about addition at:

  • brainly.com/question/1836777
  • brainly.com/question/1993757

#LearnwithBrainly

7 0
3 years ago
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7 0
3 years ago
Two vertical poles of lengths 11 ft and 14 ft stand 16 ft apart. A cable reaches from the top of one pole to some point on the g
Alex17521 [72]

We are given

total length of cable is 30 feet

and this cable is on hypotenuse sides of the triangles

so, we can draw triangle as

Let's assume those hypotenuse as 'a' and 'b'

so, we will have

a+b=30

now, we can find 'a' and 'b' from triangle

Smaller triangle:

a=\sqrt{x^2+11^2}

Larger triangle:

b=\sqrt{(16-x)^2+14^2}

we know that

a+b=30

so, we can plug this value

and we get

\sqrt{x^2+11^2}+\sqrt{(16-x)^2+14^2} =30

now, we can solve for x

\left(\sqrt{x^2+11^2}\right)^2=\left(30-\sqrt{\left(16-x\right)^2+14^2}\right)^2

32x-1231=-60\sqrt{x^2-32x+452}

1024x^2-78784x+1515361=3600x^2-115200x+1627200

now, we can use quadratic formula

we get

x=\frac{-\sqrt{36416^2-1152389056}+36416}{5152},\:x=\frac{\sqrt{36416^2-1152389056}+36416}{5152}

x=4.510,x=9.627

so,

The point should be located 4.510 feet , 9.627 feet from the smaller pole to use 30 feet cable............Answer

6 0
3 years ago
- One night a theater sold 548 movie tickets. An adult's ticket costs $6.50 and a child's ticket cost $3.50.
Natasha_Volkova [10]

Answer:

Step-by-step explanation:

Let X= each ticket for adults and Y= each ticket for kids

x+y=548

6.50x+3.50y=2881

subtract x from each side leaving you with y= -x+548

Plug in for Y

6.50x+3.50(-x+548)=2881

6.50x - 3.50x + 1918= 2881

3x+1918=2881 ....subtract

3x=963 .....divide by 3

X= 321 tickets for adults

321+y=548 ...subtract 321

Y=227 childrens tickets

6 0
3 years ago
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