The formula for the radius r in terms of x . and for the maximum areas is x=2/
+4
Given that,
y forms a circle of radius r
y=2
r
r=y/2
(2-y)- forms Square Side x
(2-y) = 4x
x=(2-y)/4
Now Sum of Area's=Area of Square +Area of Circle
Sum =
r² + x²
Substitute the r and x values in above equation,
A(y)= y²/4
+(y-2)²/ 16
To maximize Area A(y)
A'(y)= 0
2y/4
+ 2(y-2)/16 =0
y/2
+ (y-2)/8 =0
y = 2
/
+4
Y max will be max, x to be maximum.
for maximum sum of areas,
x=2/
+4
Hence,The formula for the radius r in terms of x . and for the maximum areas is x=2/
+4
Learn more about Area :
brainly.com/question/28642423
#SPJ4
5.3g + 9 = 2.3g + 15
5.3g + 9 - 9 = 2.3g + 15 - 9
5.3g = 2.3g + 6
5.3g - 2.3g = 2.3g - 2.3g + 6
3g = 6
3g / 3 = 6 / 3
g = 2
A 42 24÷16 =1.5 1.5×28 =42 b i think its 78.4 im not sure
Answer:
y = 3/5 x + 2.
Step-by-step explanation:
Use the point-slope equation of a straight line:
y - y1 = m (x - x1) where m = the slope amd (x1, y1) is a point on the line.
Here:
m = (5- (-1)) / (5 - (-5))
= 6/10
= 3/5.
Substituting for m and (5, 5):
y - 5 = 3/5(x - 5)
y - 5 = 3/5x - 3
y = 3/5 x + 2.
Answer:
<
Step-by-step explanation:
-4.2 + 1.5 = -2.7 and -5.4 + 2.1 = -3.3
-2.7 is less than -3.3