Hello :
<span>g(x) = 5x² - 50x + 128
= 5(x²-10x +128/5)
= 5 (x²-10x+5²-5² +128/5)
= 5 ((x-5)² +128/5 -125/5)
y = 5 ((x-5)² - 3/5)
y= 5(x-5)² +3.....vertex form
the vertex is : (5,3)</span>
You need to find the change in x and y
change in x = 12
change in y = 16
to find the distance you use a^2+ b^2 = c^2
or in this case x^2 + y^2 = d^2
144+256 = 400
=20
so distance equals 20
I hope this helps!
Your answer is A.) for ur problem
2.3, 2.6, 2 4/5
2 4/5= 2.8
Answer:
Step-by-step explanation:
We have been given the intersection coordinates:
(7,1,-6) and perpendicular to the line x=-1+t ,y=-2+t and z=-1+t
From the condition of perpendicularity we know:
Now, we have given x=-1+t , y=-2+t and z= -1+t
Now, substituting t in the given coordinates x,y and z we get:
And