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alexandr1967 [171]
3 years ago
6

What is the fraction equivalent to 3/9?

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
3 0

Answer:

1/3 or 2/6

Step-by-step explanation:

hope this helps :)

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The graph of the function f(x)=x^2-6x shifted 2 units to the left on the graph of g(x). Select the two functions that represent
Nimfa-mama [501]
The correct answer is

g(x) =f(x+2)
And

g(x)=x^2-2x-8

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What is the slope of the line khan academy
Dmitry [639]

Answer:

The slope of a line would be your m in the equation. So, when you have your y=mx+b you would have the slop

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3 years ago
BRAINLIEST PLEASE HELP
Ne4ueva [31]

A kilogram is 100,000 times greater than a centigram

Step-by-step explanation:

The table representing the relationship between grams and its sub-units is the following:

Microgram (\mu g) = 10^{-6} grams (g)

Milligram (mg) = 10^{-3} grams (g)

Centigram (cg) = 10^{-2} grams (g)

Gram (g) = 10^0 grams (g)

Kilogram (kg) = 10^3 grams (g)

Let's now analyze the different statements given:

A microgram is 1,000 times greater than a milligram.  --> FALSE. In fact, a microgram is \frac{10^{-6}}{10^{-3}}=0.001 times a milligram, so it is 1000 times smaller than a milligram.

A milligram is 10 times greater than a centigram.  --> FALSE. In fact, a milligram is \frac{10^{-3}}{10^{-2}}=0.1 times a centigram, so it is 10 times smaller than a centigram.

A centigram is 100 times greater than a microgram.  --> FALSE. In fact, a centigram is \frac{10^{-2}}{10^{-6}}=10^4=10,000 times a microgram, so it is 10,000 greater than a microgram.

A kilogram is 100,000 times greater than a centigram. --> TRUE. In fact, a kilogram is \frac{10^3}{10^{-2}}=10^5 = 100,000 times a centigram.

Learn more about scientific notation:

brainly.com/question/5565320

brainly.com/question/5756316

brainly.com/question/2867150

#LearnwithBrainly

6 0
4 years ago
Read 2 more answers
Add the sum of 296 and 173 to their difference​
Digiron [165]
Uhh the sum would be 469....nice
4 0
3 years ago
Use sigma notation to represent the sum of a geometric series with a first term of 3 and a common ratio of . A. B. C. D.
maksim [4K]

Answer:

\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]

Step-by-step explanation:

A geometric sequence is a list of numbers having a common ratio. Each term after the first is gotten by multiplying the previous one by the common ratio.

The first term is denoted by a and the common ratio is denoted by r.

A geometric sequence has the form:

a, ar, ar², ar³, . . .

The nth term of a geometric sequence is ar^{n-1}

Therefore the sum of the first n terms is:

\Sigma_{k=1}^{n}(ar^{k-1})

Given a geometric series with a first term of 3 and a common ratio of 10/9, the sum of the first n terms is:

\Sigma_{k=1}^{n}[3(\frac{10}{9} )^{k-1}]

5 0
3 years ago
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