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drek231 [11]
3 years ago
15

Radioactive Waste The rate at which radioactive waste is entering the atmosphere at time t is decreasing and is given by Pe^-kt,

where P is the initial rate. Use the improper integral
∫^[infinity]_0 Pe^-kt dt
with P = 50 to find the total amount of the waste that will enter the atmosphere for each value of k.
k=0.04
Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
6 0

Answer:

\displaystyle{\int^{\infty}_0 {50e^{-0.04t}}\, dt}=1250

Step-by-step explanation:

Given:

T =\displaystyle{\int^{\infty}_0 {Pe^{-kt}} \, dt}

where,

T = total amount of waste

P = 50, the initial rate

k = 0.04

t = time

T =\displaystyle{\int^{\infty}_0 {50e^{-0.04t}} \, dt}

now we need to solve this integral!

T =\displaystyle{50\int^{\infty}_0 {e^{-0.04t}} \, dt}

T = \left|50\left(\dfrac{e^{-0.04t}}{-0.04}\right)\right|^{\infty}_0

T = \left|-1250e^{-0.04t}\right|^{\infty}_0

T = (-1250e^{-0.04(\infty)})-(-1250e^{-0.04(0)})

when any number has a power of negative infinity it is 0. because: a^-{\infty} = \dfrac{1}{a^{\infty}} = \dfrac{1}{\infty} = 0, like something being divided by a very large number!

T = (-1250(0))-(-1250e^0)

T = 1250

this is the total amount of waste

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