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Assoli18 [71]
3 years ago
14

CAN SOMEONE PLS HELP I RLLY NEED HELP ASAP ANY HELP WOULD BE ENOUGH PLS AND TY PLS

Mathematics
2 answers:
Semmy [17]3 years ago
4 0

Answer:

x = 25°

Step-by-step explanation:

The secant- secant angle is half the difference of the intercepted arcs, that is

x = \frac{1}{2} (80 - 30)° = 0.5 × 50° = 25°

Zinaida [17]3 years ago
4 0

Answer:

x = 25°

Step-by-step explanation:

Hope this helps

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F=1.8C+32

We are given C=-20 degrees

plugging this value in the given equation

F=1.8(-20)+32

F=-36+32=-4

F=-4 degree fahrenheit

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3 years ago
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❊ Simplify :
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<h3>Need to Do :- </h3>
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\rule{200}4

\sf\longrightarrow \small  \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 } \\\\\\\sf\longrightarrow \small  \dfrac{ x-1}{x^2-x -2x +2} +\dfrac{ x-2}{x^2-3x-2x+6} +\dfrac{ x -5}{x^2-5x -3x + 15 } \\\\\\\sf\longrightarrow\small \dfrac{ x -1}{ x ( x - 1) -2(x-1) } +\dfrac{ x-2}{x ( x -3) -2( x -3)} +\dfrac{ x -5}{ x(x-5) -3( x -5) }  \\\\\\\sf\longrightarrow \small \dfrac{ x -1}{ ( x-2) (x-1) } +\dfrac{ x-2}{( x -2)(x-3) } +\dfrac{ x -5}{ (x-3)(x-5)  } \\\\\\\sf\longrightarrow\small \dfrac{ 1}{ x-2} +\dfrac{ 1}{ x -3} +\dfrac{1}{ x -3}   \\\\\\\sf\longrightarrow   \small  \dfrac{1}{x-2} +\dfrac{2}{x-3}  \\\\\\\sf\longrightarrow   \small \dfrac{ x-3 +2(x-2)}{ ( x -3)(x-2) }  \\\\\\\sf\longrightarrow   \small \dfrac{ x - 3 +2x -4 }{ (x-3)(x-2) }     \\\\\\\sf\longrightarrow   \underset{\blue{\sf Required \ Answer  }}{\underbrace{\boxed{\pink{\frak{  \dfrac{ 3x -7}{ ( x -2)(x-3) } }}}}}

\rule{200}4

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Answer:

Step-by-step explanation:

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-p^6

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