Answer:
As in an equilateral triangle all sides are equal so 9+3x = 5x-5
9+3x = 5x-5
9+5 = 5x-3x
14 = 2x
14/2 = x
7= x
So,As we know that x is 15 so we can substitute the values 9+3x or 5x-5
9+3x
=9+3*7
=30
So, one side of the triangle = 30
Perimeter of an equilateral triangle = 3*side
=3*30 = 90
So, perimeter of the equilateral triangle = 90
group the 1st 2 terms and last 2 terms:
(Z63 -2z^2) + (9z-18)
factor out GCF:
z^2(z-2) + 9(z-2)
now factor the polynomial:
(z-2) (z^2+9)
Answer:
Step-by-step explanation:
Let the base camp is point A and boats' locations after two hours are points B and C.
By connecting the three points together we get a triangle ABC with sides:
- AB = 50*2 = 100 km
- AC = 70*2 = 140 km
The angle between AB and AC is:
- 60 + 50 = 110 degrees (opposite directions from south)
We are looking for the distance BC, which can be found by using the law of cosines:
- BC² = AB² + AC² - 2AB*AC*cos ∠BAC
- BC² = 100² + 140² - 2*100*140*cos 110°
- BC² = 39176.56 (rounded)
- BC = √39176.56 = 197.93 km (rounded)
The distance between the boats is 197.93 km.
Answer:

Step-by-step explanation:





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