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marissa [1.9K]
2 years ago
10

Q5) given that f(x) = x^2 + x and g(x) = 3x + 1, find the value of f(g(4))

Mathematics
1 answer:
Ivanshal [37]2 years ago
3 0

Answer:

169

Step-by-step explanation:

3(4)+1

=12+1

=13

f(g(4))

f(x)=x^2 ---- (13)^2

=13x13

=169

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A tire dealer sells 2 tires for as much as he paid for 3 tires. he paid $240 for a dozen tires. What is the total profit on 12 t
tester [92]
First, find how much he paid by tire.
To do so, divide what he paid by how many tires he bought like this :
240$ / 12 = 20$ per tire

Then, calculate how much he sells each tire.
To do so, start by calculating how much he paid for 3 tires:
20$ x 3 = 60$

This is the price he sells 2 tires for, therefore :
60$ / 2 = 30$
he sells his tires 30$ each.

Finally, you have to calculate the profit he made by selling 12.
We already know how much it cost, so you need to find how much money he gets selling them :
12 tires x 30$ = 360$

To find the profit, take off the amount he paid from the amount he made :
360$ - 240$ = 120$

There you go!
3 0
3 years ago
Plz help ASAP!! Explain your answer! I will mark at brainliest!!!
Vera_Pavlovna [14]

The room is not in shape of a square but a rectangle.

Question says Length is: 19 inches

Diagonal is: 20.6 inches

In a square all sides are equal

Rectangle has just two sides equal

3 0
3 years ago
NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.
Aleks [24]

Answer:

A.) 24.08 seconds

B.) 825.42 metres

Step-by-step explanation:

function of time is given as

h ( t ) = − 4.9 t 2 + 118 t + 115 .

Where a = -4.9, b = 118, c = 115

Let's assume that the trajectory of the rocket is a perfect parabola.

The time t the rocket will reach its maximum height will be at the symmetry of the parabola.

t = -b/2a

Substitute b and a into the formula

t = -118/-2(4.9)

t = 118/9.8

t = 12.041 seconds

Since NASA launches the rocket at t = 0 seconds, the time it will splash down into the ocean will be 2t.

2t = 2 × 12.041 = 24.08 seconds

Therefore, the rocket splashes down after 24.08 seconds.

B.) At maximum height, time t = 12.041s

Substitute t for 12.041 in the function

h ( t ) = − 4.9 t 2 + 118 t + 115

h(t) = -4.9(12.041)^2 + 118(12.041) + 115

h(t) = -4.9(144.98) + 118(12.041) + 115

h(t) = -710.402 + 1420.82 + 115

h(t) = 825.42 metres

Therefore, the rocket get to the peak at 825.42 metres

6 0
3 years ago
CAN SOMEBODY ANSWER SOME OF MY MATH QUESTIONS I POSTED ALREADY?
earnstyle [38]

Answer:

ok ill try

Step-by-step explanation:

3 0
3 years ago
2918+49<br> Which numbers should be used?<br><br> The estimated quotient is?
NNADVOKAT [17]

Answer: Use all numbers to add.

2918+49=2967

Estimated.... 2918+49 ≈ 3050

Hope this helps you out.

6 0
3 years ago
Read 2 more answers
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