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3 years ago

What is the measure of angle Q to the nearest whole degree? 43° 49° 53° 58°

Mathematics

1 answer:

geniusboy [140]3 years ago

3 0

Answer:

m∠Q ≈ 53°

Step-by-step explanation:

To find the measure of ∠Q, the law of cosines will need to be used. Lowercase letters represent the side lengths, while upper case letters represent angles.

In this situation, 'A' will be ∠Q. Therefore:

17² = 18² + 20² -2(18)(20)cosQ

Simplify:

289 = 324 + 400 -2(360)cosQ

Continue simplifying down:

-435 = -720cosQ

Divide both sides by '-720':

0.604 = cosQ

$cos^{-1}Q = 0.604$

m∠Q ≈ 52.83 or 53° rounded to the nearest whole degree.

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True or false? A correct answer is worth (2 pts). Explain how you know for the additional (2 pts). Using complete sentence for (

PtichkaEL [24]

answer (in words)

FALSE. the coordinate pair (5, 2) is not a solution to the equation $2x+3y=10$ . in order to figure out whether or not the statement is true or false, plug the $x$ and $y$ values from the coordinate pair (5, 2) into the given equation, $2x+3y=10$ . if both sides of the equation end up equal, the coordinate pair is a solution to the equation. if not, the coordinate pair is not a solution to that equation.

(i hope i explained that well enough, i'm better at explaining it algebraically as opposed to putting it into words lol)

answer (algebraic/steps for solving)

first, plug in 5 for $x$ in the equation $2x+3y=10$ .

$2x+3y=10$ ⇒ $2(5)+3y=10$

then plug in 2 for $y$ .

$2(5)+3y=10$ ⇒ $2(5)+3(2)=10$

now your equation is $2(5)+3(2)=10$ . all that's left to do is to simplify. you can do this in whatever order you'd like, but i'll start with multiplying 2 · 5.

$2(5)+3(2)=10$ ⇒ $10 + 3(2) = 10$

multiply 3 · 2.

$10 + 3(2) = 10$ ⇒ $10 + 6 = 10$

add 10 + 6.

$10 + 6 = 10$ ⇒ $16=10$

16 and 10 are not equal, therefore (5, 2) is not a solution to the equation $2x+3y=10$ . in order for a coordinate pair to be the solution to an equation, both sides of the equation need to end up equal after solving and simplifying.

i hope this helps! have a great rest of your day <3

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3 years ago

Pythagorean theorem digital escape, can you find the length and area and type the correct code?

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Answer:

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Step-by-step explanation:

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2 years ago

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dolphi86 [110]

Answer:

$5 \times \frac{2}{10}$

Step-by-step explanation:

The number of times 10 can go in 52 will be the whole number

$5 \times \frac{?}{?}$

10 will go in 52 5times which will be 50 remainder two.The remainder will be the numerator

$5 \times \frac{2}{?}$

The denominator will be the original denominator (the number below)

$5 \times \frac{2}{10}$

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1 year ago

Read 2 more answers

A health clinic has 3 1/2 quarts and 1 gallon of antiseptic wash in inventory.How many fluid ounces of antiseptic wash do they h

mylen [45]

1 gallon is 128 fluid ounces;
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Change the mixed unit volume of antiseptic to just one unit. Which you choose is your choice.

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3 years ago

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Which equation has the solutions x = -3 ± √3i/2 ?

Maurinko [17]

Answer:Answer is option C : [ $x^{2}$ + 3x + 3 ] =0

Note: None of options matches with given question.

instead of "-3" , there should be "- $\frac{3}{2}$ ".

Step-by-step explanation:

Note: None of options matches with given question.

instead of "-3" , there should be " $\frac{3}{2}$ ".

Here, First thing you have to observe the nature of roots.

∴ x = - $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i and x = - $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$

∴ [ x+( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) ][ x+( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + x( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i)+ x( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i) + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ]=0

∴ [ $x^{2}$ + $\frac{3}{2}$ x + $\frac{\sqrt{3}}{2}$ ix + $\frac{3}{2}$ x - $\frac{\sqrt{3}}{2}$ ix + (3- $\frac{\sqrt{3}}{2}$ i)(3+ $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + ( $\frac{3}{2}$ - $\frac{\sqrt{3}}{2}$ i)( $\frac{3}{2}$ + $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{\sqrt{3}}{2}$ i)( $\frac{\sqrt{3}}{2}$ i) ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ - ( $\frac{3}{4}$ ) $i^{2}$ ] =0

∴ [ $x^{2}$ + 3x + $\frac{9}{4}$ + ( $\frac{3}{4}$ ) ] =0

∴ [ $x^{2}$ + 3x + $\frac{12}{4}$ ] =0

∴ [ $x^{2}$ + 3x + 3 ] =0

Thus, Answer is option C : [ $x^{2}$ + 3x + 3 ] =0

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3 years ago