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3 years ago

If A is a square matrix of order 2, then det(-3A) is *

Mathematics

2 answers:

Vsevolod [243]3 years ago

6 0

Answer:

c. 9 det A

Step-by-step explanation:

Given the following data;

Since A is a square matrix of order 2, we know that n = 2

K = 3

For any scalar k;

∣kA∣ = k^{n} ∣A∣

Substituting into the equation;

∣-3A∣ = -3²∣A∣

Simplifying, we have;

∣-3A∣ = 9∣A∣

= 9 detA

Therefore, det (-3A) = 9 detA

Angelina_Jolie [31]3 years ago

4 0

Answer:

free points :D

Step-by-step explanation:

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Solve using the linear combination method (show work) 4 − 9 = 1 −4 + 6 = −2

Scilla [17]

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3 years ago

What is the ordered pair for k?

Morgarella [4.7K]

Answer:

(4, -5)

Step-by-step explanation:

Start from the origin, (0, 0). Go 4 units right and 5 units down.

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8 0

3 years ago

Read 2 more answers

Soap films and bubbles are colorful because the interference conditions depend on the angle of illumination (which we aren't cov

mylen [45]

Answer:

56.39 nm

Step-by-step explanation:

In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

$2t=(m+\frac{1}{2} ).\frac{\lambda}{n}$

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...

Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.

In order to have its longest constructive reflection at the red end (700 nm)

$t_1=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_1=\frac{1}{2} .\frac{700}{(2)*(1.33)}\\ \\ t_1=131.58\ nm$

Here we take m=0.

Similarly for the constructive reflection at the blue end (400 nm)

$t_2=(m+\frac{1}{2} ).\frac{\lambda}{2.n}\\ \\ t_2=\frac{1}{2} .\frac{400}{(2)*(1.33)}\\ \\ t_2=75.19\ nm$

Hence the thickness difference should be

$t_1-t_2=131.58-75.19=56.39 \ nm$

7 0

3 years ago

Divide (15x^2+x-8)/(3x-1)

blondinia [14]

Simplifying -15x2 + -2x + 8 = 0
Reorder the terms: 8 + -2x + -15x2 = 0 Solving 8 + -2x + -15x2 = 0 Solving for variable 'x'.
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Simplifying 2 + -3x = 0 Solving 2 + -3x = 0
Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -3x = 0 + -2
Combine like terms: 2 + -2 = 0 0 + -3x = 0 + -2 -3x = 0 + -2
Combine like terms: 0 + -2 = -2 -3x = -2
Divide each side by '-3'. x = 0.6666666667
Simplifying x = 0.6666666667
Subproblem 2
Set the factor '(4 + 5x)' equal to zero and attempt to solve:
Simplifying 4 + 5x = 0
Solving 4 + 5x = 0
Move all terms containing x to the left, all other terms to the right.
Add '-4' to each side of the equation. 4 + -4 + 5x = 0 + -4
Combine like terms: 4 + -4 = 0 0 + 5x = 0 + -4 5x = 0 + -4
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3 years ago

Pleaassseeeee helpppppp,,,,!!!!!!

Flura [38]

Surface Area (SA) of a Cylinder formula:
SA = 2*pi*r*h+2*pi*r^2
If you fill in the formula:
SA = 2*3.14*2*9+2*3.14*2^2
Simplify:
SA = 6.28*18+6.28*4
SA = 113.04 + 25.12
SA = 138.16 in
I hope I helped
If its wrong I'm super duper extra sorry!

6 0

3 years ago