Answer: AB will be parallel to A'B'.
Step-by-step explanation: We know the definition of dilation about the centre. It is defined as the enlargement or shrinken of the original figure keeping the centre of dilation or the figure as fixed.
We are given ΔUVW and AB is perpendicular to UW. Now, if we dilate the triangle about the origin, then the triangle will either enlarge or shrink keeping the centre fixed.
Let us consider the enlarged triangle, ΔU'V'W' as shown in the attached figure. Also, line AB will move to the new position A'B'. We can clearly see that both the lines are parallel to each other.
Thus, the line segments AB and A'B' will be parallel too each other.
Answer: The answer is (d) ⇒ cscx = √3
Step-by-step explanation:
∵ sinx + (cotx)(cosx) = √3
∵ sinx + (cosx/sinx)(cosx) = √3
∴ sinx + cos²x/sinx = √3
∵ cos²x = 1 - sin²x
∴ sinx + (1 - sin²x)/sinx = √3 ⇒ make L.C.M
∴ (sin²x + 1 - sin²x)/sinx = √3
∴ 1/sinx = √3
∵ 1/sinx = cscx
∴ cscx = √3
Answer:
x = 23
y = 7
z = 11
Step-by-step explanation:
Since ∆PRS ≅ ∆CFH, therefore,
m<R = m<F
13y - 1 = 90° (substitution)
Add 1 to both sides
13y - 1 + 1 = 90 + 1
13y = 91
Divide both sides by 13
13y/13 = 91/13
y = 7
Since ∆PRS ≅ ∆CFH, therefore,
PS = CH
2x - 7 = 39 (substitution)
Add 7 to both sides
2x - 7 + 7 = 39 + 7
2x = 46
Divide both sides by 2
2x/2 = 46/2
x = 23
Since ∆PRS ≅ ∆CFH, therefore,
m<S = m<H
Find m<S
m<S = 180 - (m<P + m<R) (sum of ∆)
m<S = 180 - (28 + (13y - 1)) (substitution)
Plug in the value of y
m<S = 180 - (28 + (13)(7) - 1))
m<S = 180 - (28 + 91 - 1)
m<S = 180 - 118
m<S = 62°
Therefore, since m<S = m<H,
62° = 6z - 4 (substitution)
Add 4 to both sides
62 + 4 = 6z - 4 + 4
66 = 6z
Divide both sides by 6
66/6 = 6z/6
11 = z
Answer: A. 87 feet
Step-by-step explanation:
1. You can find the t value of the vertex of the parabola as following:

2. Substitute values:
a=-16
b=70
Then:

3. Substitute the vaue obtained into the equation given in the problem. Therefore, you obtain the following result:

4. To the nearest foot:
h=87 feet