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matrenka [14]
2 years ago
10

Question 2

Mathematics
1 answer:
BabaBlast [244]2 years ago
6 0

Answer:

The equation of the required line is y = x + 5

Step-by-step explanation:

The equation of the given line is y = x - 2

The required line = A line parallel to the given line

The point through which the required line passes = (-3, 2)

The general form of the equation of a straight line, is y = m·x + c

Where;

m = The slope of the line

By comparison, the slope of the given line, m = 1

When two lines are parallel, their slope are equal

Therefore, the slope of the required line = m = 1

The equation of the required line in point and slope form is therefore;

y - 2 = x - (-3) = x + 3

∴y = x + 3 + 2 = x + 5

The equation of the required line is therefore;

y = x + 5.

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vazorg [7]

Answer:

The ball will go to maximum height of 56.25 meters.

Step-by-step explanation:

It is given that, a ball is thrown vertically upward from the ground. Initial velocity of the ball, v = 60 ft/sec

Initial height is 0 as the ball is thrown from ground. The equation of projectile is given by :

h(t)=-16t^2+vt+h

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We need to find the maximum height reached by the ball. For maximum height,

\dfrac{dh(t)}{dt}=0

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h(t)=-16(1.875)^2+60(1.875)

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So, the ball will go to maximum height of 56.25 meters. Hence, this is teh required solution.

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Step-by-step explanation:

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Step-by-step explanation:

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