Step-by-step explanation:
Correct option is
Correct option isD
Correct option isDLMN=30
Correct option isDLMN=30 Solve:
Correct option isDLMN=30 Solve: Given,
Correct option isDLMN=30 Solve: Given, L=∑r=72400log7(rr+1)
Correct option isDLMN=30 Solve: Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401)
Correct option isDLMN=30 Solve: Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401) We know that
Correct option isDLMN=30 Solve: Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401) We know that loga+logb=logab
Correct option isDLMN=30 Solve: Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401) We know that loga+logb=logab⇒L=log7(78)×(89)×(910)×…×(2400401)
Correct option isDLMN=30 Solve: Given, L=∑r=72400log7(rr+1)⇒L=log7(78)+log7(89)+log7(910)+−⋯+log7(24002401) We know that loga+logb=logab⇒L=log7(78)×(89)×(910)×…×(2400401)⇒L=log7(
I have the same problem. I think it is 4.
The answer is 2.
Hope this helps! :)
If Keith had 1 1/2 cups, he can't use <span>5 2/3 cups. He cant use more than what he had. There is error in this question.</span>