Quick:Three different factorizations of 32m+56mp.

I don't understand this I have spent many points on this same question so this time I will be giving brainliest for the first co

Marrrta [24]

Given:

$|3+4 i|+|3-4 i|+|-3+4 i|+|-3-4 i|$

Solution:

Complex formula:

$|a+b i|=\sqrt{(a+b i)(a-b i)}=\sqrt{a^{2}+b^{2}}$

Let us simplify one by one.

$|3+4 i|=\sqrt{3^{2}+4^{2}}$

$=\sqrt{25}$

|3 + 4i| = 5

$|3-4 i|=\sqrt{3^{2}+(-4)^{2}}$

$=\sqrt{25}$

|3 - 4i| = 5

$|-3+4 i|=\sqrt{(-3)^{2}+4^{2}}$

$=\sqrt{25}$

|-3 + 4i| = 5

$|-3-4 i|=\sqrt{(-3)^{2}+(-4)^{2}}$

$=\sqrt{25}$

|-3 - 4i| = 5

Substitute these in the given expression:

$|3+4 i|+|3-4 i|+|-3+4 i|+|-3-4 i|=5+5+5+5$

$=20$

The solution of the expression is 20.

8 0

2 years ago

What is the range of the function y= 2e^x -1 ?

PtichkaEL [24]

The range is all real number greater than - 1

6 0

3 years ago

Read 2 more answers

Jeremy invests $8, 500 into an account with a 2.4% interest rate that is compounded quarterly. How much money will be in

sertanlavr [38]

Answer:

$9,812.29

Step-by-step explanation:

The amount in Jeremy's account can be computed using the compound interest formula.

__

<h3>account value</h3>

The formula for the value of an account earning compound interest at annual rate r, compounded n times per year for t years is ...

A = P(1 +r/n)^(nt)

where P is the principal invested.

__

<h3>formula application</h3>

When P=$8500, r=0.024, n=4, t=6, the formula becomes ...

A = $8500(1 +0.024/4)^(4·6) = $8500(1.006^24) ≈ $9812.29

There will be $9,812.29 in this account after 6 years.

5 0

1 year ago

How to count fast from 82-199

boyakko [2]

Just skipppppp counttttt

3 0

2 years ago

Two trains move between two towns. It takes the first train 2 hr 48 min and it takes the second 4 hr 40 min. The rate of the fir

Umnica [9.8K]

Answer:

182 miles.

Step-by-step explanation:

Given:

Two trains move between two towns.

Time taken by first train = 2 hr 48 minutes =

Change minute into hour:

60 minute = 1 hour

1 minute = $\frac{1}{60}$

48 minutes = $\frac{1}{60}\times48=\frac{48}{60} =0.8\ hour$

Time taken by first train in hour = $2+0.8=2.8\ hours$

Time taken by second train = 4 hr 40 minutes

Similarly, 40 minutes = $\frac{40}{60} =0.67\ hour$

Time taken by second train in hour = $4+0.67=4.67\ hours$

The rate of the first train is 26 mph more than that of the second train.

Question asked:

What is the distance between these towns ?

Solution:

Let speed of second train = $x\ miles\ per\ hour$

<u>As the speed of the first train is 26 mph more than that of the second train. </u>

Speed of first train = $26+x\ miles\ per\ hour$

As two trains move between two towns means distance traveled by both train is same.

By using : $Distance=speed\times time$

Distance traveled by first train = Distance traveled by second train

$speed\times time$ =

$(26+x)2.8=x\times4.67$

$26\times2.8+x\times2.8=4.67x\\72.8+2.8x=4.67x\\$

Subtracting both sides by $2.8x$

$72.8=1.87x$

Dividing both sides by 1.87

$x=38.93$

Speed of second train = 38.93 miles per hour

$Distance=speed\times time$

= 38.93 $\times$ 4.67

= 181.80 miles.

Thus, the distance between these towns is 182 miles (nearest whole number).

3 0

3 years ago