PLEASE HELP THIS IS VERY IMPORTANT I WILL GIVE YOU BRAIN THING IF ITS CORRECT (you can use a calculator if you want) <3

Mathematics

2 answers:

Temka [501]3 years ago

7 0

Answer:

Answers below

Step-by-step explanation:

A. He is incorrect because 1.875÷500≈2÷500=0.004, so you know he is wrong.

B. 1.875÷500=0.00375. Each piece is 0.00375 inches thick

Ilia_Sergeevich [38]3 years ago

5 0

Answer:

A. Diego's answer is not correct.

B. 0.00375

Step-by-step explanation:

a. As I counted the thickness of the paper I realized that 0.015 inches is way too think because if we stacked 500 of those it would be 7.5 inches tall.

b. 1.875 ÷ 500 = 0.00375. so that is your answer

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PLEASE HELP ME WITH THIS ONE ASAP PLEASE AND THANK YOU thanks in advance

Andreyy89

Answer:

ok so 10 times 4 equals 40 and then 40 times six equals 240 but I don't know what standard notation is

7 0

3 years ago

Read 2 more answers

In a free-fall experiment, an object is dropped from a height of h = 400 feet. A camera on the ground 500 ft from the point of i

PilotLPTM [1.2K]

Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s

the only force acting on the object, is gravity, using feet will then be -32ft/s²,

was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues

so, we'll do the integral to get v(t) then

$\bf \displaystyle \int -32\cdot dt\implies -32t+C
\\\\\\
\textit{object moves from \underline{rest}, so velocity is 0 at 0secs}
\\\\\\
-32(0)+C=0\implies C=0\implies \boxed{v(t)=-32t}
\\\\\\
\textit{now to get the positional s(t)}
\\\\\\
\displaystyle \int -32t\cdot dt\implies -16t^2+C
\\\\\\
\textit{the initial \underline{position} was 400ft away at 0secs}
\\\\\\
-16(0)^2+C=400\implies C=400\implies \boxed{s(t)=-16t^2+400}$

when will it reach the ground level? let's set s(t) = 0

$\bf s(t)=-16t^2+400\implies 0=-16t^2+400\implies \cfrac{-400}{-16}=t^2
\\\\\\
25=t^2\implies \boxed{5=t}$

part B) check the picture below