Since "PROBABILITY" has 11 letters in it, then every letter has 1/11 chances of getting picked, so the chances of getting an O tile would be 1/11, same for getting a B tile. But if you were to get both of them consecutively, then the chances would be 1/11 of 1/11 because you have 1/11 of a chance to get and O and then 1/11 of a chance to get a B. So you would be looking for 1/11 of 1/11, which means multiplying the divisor, 11*11=121. Therefore, you should have 1/121 chance of getting an O and B tile.
Answer:
C. 26 Inches
Step-by-step explanation:
Using process of elimination you can tell the answer. 26*(13+3)=416
Answer:
B) The sum of the squared residuals
Step-by-step explanation:
Least Square Regression Line is drawn through a bivariate data(Data in two variables) plotted on a graph to explain the relation between the explanatory variable(x) and the response variable(y).
Not all the points will lie on the Least Square Regression Line in all cases. Some points will be above line and some points will be below the line. The vertical distance between the points and the line is known as residual. Since, some points are above the line and some are below, the sum of residuals is always zero for a Least Square Regression Line.
Since, we want to minimize the overall error(residual) so that our line is as close to the points as possible, considering the sum of residuals wont be helpful as it will always be zero. So we square the residuals first and them sum them. This always gives a positive value. The Least Square Regression Line minimizes this sum of residuals and the result is a line of Best Fit for the bivariate data.
Therefore, option B gives the correct answer.
8 39/40
=8+39/40
=8•40/40+39/40
=320/40+39/40
=320+39/40
=359/40
=8.975
The answer is 8 39/40=8.975
If you begin with the basic equation of a vertical parabola: y-k=a(x-h)^2, where (h,k) is the vertex, then that equation, when the vertex is (-3,-2), is
y + 2 = a (x + 3)^2. If we solve this for y, we get
y = a(x+3)^2 - 2. Thus, eliminate answers A and D. That leaves B, since B correctly shows (x+3)^2.
