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3 years ago

65,018-_______ones......

Mathematics

2 answers:

kap26 [50]3 years ago

7 0

Answer:

8 is at ones place

hope this will help you

Step-by-step explanation:

have a great day

Fudgin [204]3 years ago

4 0

Answer:

Step-by-step explanation:

If you see here in the number 65,018 we can see that if we put it in the place value system then we can see that 8 is on the ones place

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What is 2/9 = 4/x+8 i dont get this fraction solving

Dmitriy789 [7]

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$\frac{2}{9} = \frac{4}{x + 8} \\$

$\frac{4}{x + 8} = \frac{2}{9} \\$

Inverse both sides

$\frac{x + 8}{4} = \frac{9}{2} \\$

Multiply sides by 4

$4 \times \frac{x + 8}{4} = 4 \times \frac{9}{2} \\$

$x + 8 = 2 \times 9$

$x + 8 = 18$

Subtract sides 8

$x + 8 - 8 = 18 - 8$

$x = 10$

Done...

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3 0

3 years ago

During a film festival, the first film ticket is priced at $16, and each additional ticket is $11. if Rico spends $71, then how

ArbitrLikvidat [17]

Rico purchased a total of 6 tickets.

7 0

3 years ago

Read 2 more answers

Solve 6 sin((π/5)x)=5 for the four smallest positive solutions

cupoosta [38]

Answer:

1.568, 3.432, 11.568, 13.432

Step-by-step explanation:

Divide equation $6\sin\left(\dfrac{\pi }{5}x\right)=5$ by 6:

$\sin\left(\dfrac{\pi }{5}x\right)=\dfrac{5}{6}.$

Then

$\dfrac{\pi }{5}x=(-1)^k\arcsin\left(\dfrac{5}{6}\right)+\pi k,\ k\in Z,$

$x=(-1)^k\dfrac{5}{\pi }\arcsin\left(\dfrac{5}{6}\right)+5k,\ k\in Z.$

Since $\arcsin\left(\dfrac{5}{6}\right)\approx 56^{\circ}\approx \dfrac{\pi }{3.2},$

four smallest positive solutions are

1. $\dfrac{5}{3.2}\approx 1.568,\ k=0;$

2. $\dfrac{-5}{3.2}+5\approx 3.432,\ k=1;$

3. $\dfrac{5}{3.2}+10\approx 11.568,\ k=2;$

4. $\dfrac{-5}{3.2}+15\approx 13.432,\ k=3.$

3 0

3 years ago

Let E = {(x, y) e R2|xy > 0}. Determine whether E is a subspace of R2 . X3

gayaneshka [121]

Answer:

E is not a subspace of $\mathbb{R}^2$

Step-by-step explanation:

E is not a subspace of $\mathbb{R}^2$

In order to see this, we must find two points (a,b), (c,d) in E such that (a,b) + (c,d) is not in E.

Consider

(a,b) = (1,1)

(c,d) = (-1,-1)

It is easy to see that both (a,b) and (c,d) are in E since 1*1>0 and (1-)*(-1)>0.

But (a,b) + (c,d) = (1-1, 1-1) = (0,0)

and (0,0) is not in E.

By the way, it can be proved that in any vector space all sub spaces must have the vector zero.

5 0

3 years ago

What is the area of this figure?

nirvana33 [79]

Answer:

602

Step-by-step explanation:

First find area of the rectangle portion

L x W

22 x 15

330

Second find area of trapezoid

B1+B2/2 times height

12+22/2 times 16

34/2 times 16

17 times 16

272

Lastly, add areas together

4 0

3 years ago