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ASHA 777 [7]
3 years ago
15

Propane burns in air to form water vapor and another gas. What is the volume of the water vapor at 500°C and 1 atm?​

Chemistry
1 answer:
kakasveta [241]3 years ago
7 0

Answer:

253.85 L

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

C₃H₈ + 5O₂ —> 3CO₂ + 4H₂O

From the balanced equation above, 4 moles of water vapor were produced.

Finally, we shall determine the volume of the water vapor produced as follow:

Mole water vapor (n) = 4 moles

Pressure (P) = 1 atm

Temperature (T) = 500 °C = 500 °C + 273 = 773 K

Gas constant (R) = 0.821 atm.L/Kmol

Volume (V) =?

PV = nRT

1 × V = 4 ×0.0821 × 773

V = 253.85 L

Thus, the volume of water vapor obtained is 253.85 L

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Which hydrocarbon belongs to the Alkyne homologous series?
Ira Lisetskai [31]

Answer:

(A) CHCH

Explanation:

Hello,

Alkynes are formed when triple bonds are formed between carbons, it means that due to the triple bonds, three bonds are already exhausted and carbon atoms need four bonds to attain the octet, for that reason, an extra bond is allowed. Now, such extra bond, when talking about hydrocarbons is filled with hydrogens, for that reason the alkyne should be (A) CHCH as it also accomplishes the following formula which is not accomplished by the rest of the options:

C_nH_{2n-2}

Since n=2, we have:

C_2H_2

Which matches with CHCH.

Best regards.

3 0
3 years ago
Based on the Lewis/electron dot representation of the two atoms, predict the ratio of metal cationic (+) atom to nonmetal anioni
Aleks [24]

The answer is 1:1

I got it right

8 0
3 years ago
What is the equilibrium constant expression for the following reaction?
Gwar [14]

Answer:

Kc = [CO][Cl₂]/[COCl].

Kp = P(CO)P(Cl₂)/P(COCl).

Explanation:

For the balanced reaction:

COCl₂(g) ⇄ CO(g) + Cl₂(g).

The equilibrium constant can be expressed as concentration equilibrium constant (Kc) or pressure equilibrium constant (Kp).

The equilibrium constant is the ratio of the product of products concentrations to the product of the reactants concentrations.

Kc = [CO][Cl₂]/[COCl].

Kp = P(CO)P(Cl₂)/P(COCl).

5 0
3 years ago
The steps of the Scientific Method include question, hypothesis, experiment,
antiseptic1488 [7]

Answer:

True

Explanation:

Define purpose.

Construct hypothesis.

Test the hypothesis and collect data.

Analyze data.

Draw conclusion.

Communicate results.

4 0
3 years ago
Read 2 more answers
Consider the following unbalanced equation. What is the standard free energy for the reaction of 7. 2 moles of al2o3(s) at 298k?
Lorico [155]

for the following unbalanced equation.5800 kj is  the standard free energy for the reaction of 7. 2 moles of al2o3(s) at 298k

 First, let's balance the equation. Both sides must have the same amount of each element, so: Al₂O(s) + 3CO(g) 2Al(s) + 3CO2(g)

The free energy can be calculated by: AG = AH-TAS Where AH is the enthalpy of the reaction, and AS is the entropy of the reaction.

Al2O3(s): Hf=-1676.0 kJ/mol; S = 50.92 J/mol.K Al(s): Hf = 0.00; S° = 28.3 J/mol.K

CO(g): Hf=-110.5 kJ/mol; S = 197.6 J/mol.K

CO2(g): Hf=-393.5 kJ/mol; S = 213.6 J/mol.K

AH = Σn*Hf products - En*Hf reactants (n is the coefficient of the compound).

AH = (3*(-393.5) + 2*0) - (3*(-110.5) + (-1676)) = 827KJ

AS = {n*S* products - Σn*S° reactants

AS = (3*213.6 +2*28.3) - (3*197.6 + 50.92) = 53.68J/K = 0.05368 kJ/K

AG 827-298*0.05368 AG = 811 KJ

Which is the free energy for 1 mol of Al2O3

1 mol of Al2O3=811 KJ X 7.2 moles of Al2O3

By a simple direct three rule:  standard free energy is x = 5839.2 kJ = 5800 kJ

Learn more about  standard free energy here:

brainly.com/question/10012881

#SPJ4

6 0
1 year ago
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