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Alexus [3.1K]
3 years ago
12

Is the number of total molecules on the side of a balanced equation always equal to the number of total molecules on the right s

ide of the equation?
Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
3 0

Answer:

if it is accurately balanced it is supposed to be

Explanation:

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A student states that this structural formula represents a hydrocarbon.
Andreyy89
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the answer is Yes, a hydrocarbon is any compound that contains hydrogen and oxygen.

5 0
3 years ago
Which type of wave to support the idea that light is also made of waves
Alex

Answer:

my d comes in waves

Explanation:

7 0
3 years ago
Calculate the moles of calcium chloride (CaCl2) needed to react in order to produce 85.00 grams of calcium carbonate (CaCO3). us
BartSMP [9]

Answer:

0.85 mole

Explanation:

Step 1:

The balanced equation for the reaction of CaCl2 to produce CaCO3. This is illustrated below:

When CaCl2 react with Na2CO3, CaCO3 is produced according to the balanced equation:

CaCl2 + Na2CO3 -> CaCO3 + 2NaCl

Step 2:

Conversion of 85g of CaCO3 to mole. This is illustrated below:

Molar Mass of CaCO3 = 40 + 12 + (16x3) = 40 + 12 + 48 = 100g/mol

Mass of CaCO3 = 85g

Moles of CaCO3 =?

Number of mole = Mass /Molar Mass

Mole of CaCO3 = 85/100

Mole of caco= 0.85 mole

Step 3:

Determination of the number of mole of CaCl2 needed to produce 85g (i.e 0. 85 mole) of CaCO3.

This is illustrated below :

From the balanced equation above,

1 mole of CaCl2 reacted to produced 1 mole of CaCO3.

Therefore, 0.85 mole of CaCl2 will also react to produce 0.85 mole of CaCO3.

From the calculations made above, 0.85 mole of CaCl2 is needed to produce 85g of CaCO3

5 0
3 years ago
Read 2 more answers
A pH scale reading 13 indicates a ______
lukranit [14]

Answer:

A pH scale reading 13 indicates a strong base.

Explanation:

From my understanding:

1 -4 is a strong acid

4 - 7 is weak acid

7 - 9 is a weak base

9 - 14 is a strong base

6 0
2 years ago
Read 2 more answers
if a lead can be extrated with 92.5% efficiency,what is the mass of ore required to make a lead sphere with 750%cm radius
Lady_Fox [76]
The mass of ore required is 21 700 t.

r = 750 cm

V = \frac{4}{3}  \pi  r^{3} = \frac{4}{3}  \pi  (750 cm)^{3} = 1.767 × 10⁹ cm³

The density of lead is 11.34 g/cm³.

So mass of lead sphere = 1.767 × 10⁹ cm³ × \frac{11.34 g}{1 cm^{3} } = 2.004 ×10¹⁰ g

2.004 ×10¹⁰ g × \frac{1 kg}{1000 g} = 2.004 × 10⁷ kg

2.004 × 10⁷ kg × \frac{1 t}{1000 kg} = 2.004 × 10⁴ t

92.5% efficiency means 92.5 t Pb per 100 t of ore.

Mass of ore = 2.004 × 10⁴ t Pb ×\frac{100 tore}{92.5 t Pb} = 2.17 × 10⁴ t ore = 21 700 t ore

6 0
3 years ago
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