Question

Identify the substances that will appear in the equilibrium constant expression for the equation: 2Ag+(aq)+Zn(s)<->Zn2+(aq)+2Ag(s)

Answer 1

Hey there!

We Know that:

 2 Ag⁺(aq) + Zn(s) <-> Zn²⁺(aq)+2 Ag(s)

The equilibrium expression for the reaction is:

Kc =  [ Zn⁺² ]  /  [Ag⁺ ]²

Hope that helps!

Answer 2

Answer : The expression for equilibrium constant for the given reaction is,

$K_c=\frac{[Zn^{2+}]}{[Ag^+]^2}$

Explanation :

The given balanced chemical reaction is,

$2Ag^+(aq)+Zn(s)\rightleftharpoons Zn^{2+}(aq)+2Ag(s)$

In the expression of equilibrium constant, only aqueous and gaseous substances are included. pure liquids and solids are not included.

Thus, the expression for equilibrium constant for the given reaction is,

$K_c=\frac{[Zn^{2+}]}{[Ag^+]^2}$