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zhuklara [117]
3 years ago
9

Identify the substances that will appear in the equilibrium constant expression for the equation: 2Ag+(aq)+Zn(s)<->Zn2+(aq

)+2Ag(s)
Chemistry
2 answers:
Simora [160]3 years ago
8 0

Hey there!


We Know that:



 2 Ag⁺(aq) + Zn(s) <-> Zn²⁺(aq)+2 Ag(s)


The equilibrium expression for the reaction is:



Kc =  [ Zn⁺² ]  /  [Ag⁺ ]²


Hope that helps!

astraxan [27]3 years ago
6 0

Answer : The expression for equilibrium constant for the given reaction is,

K_c=\frac{[Zn^{2+}]}{[Ag^+]^2}

Explanation :

The given balanced chemical reaction is,

2Ag^+(aq)+Zn(s)\rightleftharpoons Zn^{2+}(aq)+2Ag(s)

In the expression of equilibrium constant, only aqueous and gaseous substances are included. pure liquids and solids are not included.

Thus, the expression for equilibrium constant for the given reaction is,

K_c=\frac{[Zn^{2+}]}{[Ag^+]^2}

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Answer:

C.) Alpha, beta, and gamma particles

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A dense shield of aluminium can protect Cole from all the listed types of radiation produced from the radioactive particles.

A radioactive protector has very unique and specie ability to contain and prevent the movement of radiations of any types from going into the body.

The strongest and most penetrating radiations are the gamma rays. Any material that can prevent the movement of these rays can halt alpha and beta particles too.

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4 years ago
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A highly concentrated solution from which dilutions are typically made for laboratory used is called a what?
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Phosgene, a poisonous gas, when heated will decompose into carbon monoxide and chlorine in a reversible reaction: COCl2 (g) &lt;
Advocard [28]

Answer:

8.08 × 10⁻⁴

Explanation:

Let's consider the following reaction.

COCl₂(g) ⇄ CO (g) + Cl₂(g)

The initial concentration of phosgene is:

M = 2.00 mol / 1.00 L = 2.00 M

We can find the final concentrations using an ICE chart.

     COCl₂(g) ⇄ CO (g) + Cl₂(g)

I       2.00            0            0

C        -x             +x           +x

E    2.00 -x          x             x

The equilibrium concentration of Cl₂, x, is 0.0398 mol / 1.00 L = 0.0398 M.

The concentrations at equilibrium are:

[COCl₂] = 2.00 -x = 1.96 M

[CO] = [Cl₂] = 0.0398 M

The equilibrium constant (Keq) is:

Keq = [CO].[Cl₂]/[COCl₂]

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3 years ago
How many grams of hydrogen chloride can be produced from 1g of hydrogen and 55g of chlorine? What is the limiting reactant?
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Answer:

The limiting reactant is hydrogen, and the grams HCl produced is 36.175 g.

Explanation:

Balanced equation is 2 H + Cl2 = 2 HCl.

First thing, convert grams to moles via using molar mass.

Molar mass for hydrogen is 1.0079 g/mol. 1g x 1 mol / 1.0079 g = 0.99216 mol.

Molar mass for chlorine is 70.906 g/mol. 55g x 1 mol / 70.906 g = 0.7756748 mol.

Next, determine which is the limiting reactant - probably the fastest way to do it is just to take one of the reactants, say it's the limiting one, and calculate how much of the other reactant would be needed if that really was the limiting reactant, and then compare it to the actual moles of reactant available.

If hydrogen was the limiting reactant at 0.992 mol, you'd need .496 mol of Cl2 to complete the reaction.

If chloride was the limiting reactant at 0.776 mol, you'd need 1.55 mol of H to complete the reaction.

Comparing these numbers to the amounts we actually have available, the limiting reactant is hydrogen.

Once you've determined that, just plug in the amounts to the balanced equation to get the number of moles of HCL produced, which in this case, is just 0.992 mol.

Now, reverse the process that you took to get the moles of reactant, and you have the grams of product produced.

0.992 mol x 36.4609 g / 1 mol = 36.175 g.

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