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zhuklara [117]
3 years ago
9

Identify the substances that will appear in the equilibrium constant expression for the equation: 2Ag+(aq)+Zn(s)<->Zn2+(aq

)+2Ag(s)
Chemistry
2 answers:
Simora [160]3 years ago
8 0

Hey there!


We Know that:



 2 Ag⁺(aq) + Zn(s) <-> Zn²⁺(aq)+2 Ag(s)


The equilibrium expression for the reaction is:



Kc =  [ Zn⁺² ]  /  [Ag⁺ ]²


Hope that helps!

astraxan [27]3 years ago
6 0

Answer : The expression for equilibrium constant for the given reaction is,

K_c=\frac{[Zn^{2+}]}{[Ag^+]^2}

Explanation :

The given balanced chemical reaction is,

2Ag^+(aq)+Zn(s)\rightleftharpoons Zn^{2+}(aq)+2Ag(s)

In the expression of equilibrium constant, only aqueous and gaseous substances are included. pure liquids and solids are not included.

Thus, the expression for equilibrium constant for the given reaction is,

K_c=\frac{[Zn^{2+}]}{[Ag^+]^2}

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In order for a solute to dissolve in a solvent, what must be true?
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An oxide of phosphorus contains 56.4% phosphorus and 43.6% oxygen. It's relative molecular mass is 220. Find both the empirical
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7 0
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1A. A strontium hydroxide solution is prepared by dissolving 10.45 g of Sr(OH)2 in water to make 41.00 mL of solution. What is t
horrorfan [7]

Answer:

1. 0.00352 M

2. 2HNO3(aq) + Sr(OH)2(aq) -----> Sr(NO3)2(aq) + 2H2O(l)

3. 0.00534 M

Explanation:

1.

Mass of strontium hydroxide= 10.45 g

Volume of solution = 41.00 ml

Number of moles = mass of Sr(OH)2/molar mass of Sr(OH)2 = 10.45g/121.63 g/mol= 0.0859 moles

Molarity= number of moles × volume = 0.0859 ×41/1000 = 0.00352 M

2.

2HNO3(aq) + Sr(OH)2(aq) -----> Sr(NO3)2(aq) + 2H2O(l)

3.

Concentration of acid CA= the unknown

Volume of acid VA= 31.5 ml

Concentration of base CB= 0.00352 M

Volume of base VB= 23.9 ml

Number of moles of acid NA= 2

Number of moles of base NB= 1

From;

CAVA/CBVB = NA/NB

CAVANB= CBVBNA

CA= CBVBNA/VANB

CA= 0.00352 × 23.9 ×2/31.5 ×1

CA= 0.00534 M

7 0
3 years ago
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