Identify the substances that will appear in the equilibrium constant expression for the equation: 2Ag+(aq)+Zn(s)<->Zn2+(aq
)+2Ag(s)
2 answers:
Hey there!
We Know that:
2 Ag⁺(aq) + Zn(s) <-> Zn²⁺(aq)+2 Ag(s)
The equilibrium expression for the reaction is:
Kc = [ Zn⁺² ] / [Ag⁺ ]²
Hope that helps!
Answer : The expression for equilibrium constant for the given reaction is,
![K_c=\frac{[Zn^{2+}]}{[Ag^+]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BZn%5E%7B2%2B%7D%5D%7D%7B%5BAg%5E%2B%5D%5E2%7D)
Explanation :
The given balanced chemical reaction is,

In the expression of equilibrium constant, only aqueous and gaseous substances are included. pure liquids and solids are not included.
Thus, the expression for equilibrium constant for the given reaction is,
![K_c=\frac{[Zn^{2+}]}{[Ag^+]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BZn%5E%7B2%2B%7D%5D%7D%7B%5BAg%5E%2B%5D%5E2%7D)
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Hello,
The answer is false