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zhuklara [117]
3 years ago
9

Identify the substances that will appear in the equilibrium constant expression for the equation: 2Ag+(aq)+Zn(s)<->Zn2+(aq

)+2Ag(s)
Chemistry
2 answers:
Simora [160]3 years ago
8 0

Hey there!


We Know that:



 2 Ag⁺(aq) + Zn(s) <-> Zn²⁺(aq)+2 Ag(s)


The equilibrium expression for the reaction is:



Kc =  [ Zn⁺² ]  /  [Ag⁺ ]²


Hope that helps!

astraxan [27]3 years ago
6 0

Answer : The expression for equilibrium constant for the given reaction is,

K_c=\frac{[Zn^{2+}]}{[Ag^+]^2}

Explanation :

The given balanced chemical reaction is,

2Ag^+(aq)+Zn(s)\rightleftharpoons Zn^{2+}(aq)+2Ag(s)

In the expression of equilibrium constant, only aqueous and gaseous substances are included. pure liquids and solids are not included.

Thus, the expression for equilibrium constant for the given reaction is,

K_c=\frac{[Zn^{2+}]}{[Ag^+]^2}

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3 years ago
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It is an example of double displacement reaction because in this reaction a positive cation and a negative anion of the two reactants exchange their places to form two new products.

Option B reaction : SnO_2+2H_2\rightarrow Sn+2H_2O

It is an example of single displacement reaction.

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It is an example of combination reaction because in this reaction two reactants react to give a single product.

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It is an example of decomposition reaction because in this reaction a single reactant decomposes into two or more products.

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The answer please thank you
otez555 [7]

Answer:

B

Explanation:

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