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3 years ago

The Peoples of Brainly are untrustworthy.

Mathematics

2 answers:

Semmy [17]3 years ago

8 0

Answer:

Very much agreed

Step-by-step explanation:

mestny [16]3 years ago

3 0

Answer:

50 + 10 + 60 + 1 = 121

121 = 11^2

1 + 1 + 2 = 4

There is 4 catagories in your "question"

Coincidence? I think not

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Which of the following give the highest future value is 6000000 is invested at 6% for 3 years

Blababa [14]

Answer:

$5084745.76271

Step-by-step explanation:

Given data

Final amount= $6000000

Rate=6%

Time= 3 years

Now let us find the initial amount which is the principal

using the simple interest formula we have

6000000 = P(1+0.06*3)

6000000 =P(1+0.18)

6000000 =P*1.18

P= 6000000 /1.18

P=$5084745.76271

Hence the initial deposite is $5084745.76271

3 0

3 years ago

Autumn is making a fruit salad. Peaches cost 0.75 each and blueberries cost $1.50 a package. Autumn spends 11.25 dollars and buy

Harman [31]

5 peaces and 5 blueberry packages 0.75*5=3.75. 1.50*5=7.5. 3.75+7.5=11.25

6 0

3 years ago

Read 2 more answers

The fire department needs to rescue a man from a house. There is a large, unstable puddle below the house. The ladder needs to b

nevsk [136]

Answer: 100 feet

Step-by-step explanation:

60+40=100

5 0

3 years ago

Read 2 more answers

16 points - Question in photo!

storchak [24]

5.394e+13 hope this helps

6 0

4 years ago

Read 2 more answers

Confidence Interval Application Many people feel that the drying of pavement marking paint is much too slow. You spend several d

djyliett [7]

Answer:

The sample size is $n =33$

Step-by-step explanation:

From the question we are told that

The margin of error is E = 1.5 seconds

The standard deviation is s = 4 seconds

Given that the confidence level is 97% then the level of significance is mathematically represented as

$\alpha =( 100 -97)\%$

=> $\alpha = 0.03$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 2.17$

Generally the sample size is mathematically represented as

$n =[ \frac{Z_{\frac{\sigma }{2 } } * \sigma }{E} ]^2$

=> $n =[ \frac{2.17 * 4 }{1.5} ]^2$

=> $n =33$

7 0

3 years ago