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Andrew [12]
3 years ago
12

Help me with this pleaseee.

Mathematics
2 answers:
katrin [286]3 years ago
8 0
The answer to that is b
Rom4ik [11]3 years ago
6 0

Answer:

i think it would be B bc its not A or C

Step-by-step explanation:

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A pizza parlor sold 38 1/2 pizzas during a dinner hour. If each pizza contained 8 slices, how many slices of pizza were sold?
MArishka [77]
308 slices would be sold.
38*8= 304, plus 4 slices in half a pizza makes 308 slices.
8 0
3 years ago
Read 2 more answers
Find the value of x. Express your answer in simplest radical form
klemol [59]
Since x=x, this is an isosceles right triangle.  By the Pythagorean Theorem:

h^2=a^2+b^2  (the hypotenuse squared is equal to the sum of the squared sides)

5^2=x^2+x^2

25=2x^2

2x^2=25

x^2=25/2

x=√(25/2)

x=5/√2  now if we rationalize the denominator...

x=(5√2)/(√2√2)

x=(5√2)/2
7 0
4 years ago
A bag contains 5 red marbles, 8 blue marbles and 6 green marbles. If three marbles are drawn out of the bag, what is the probabi
Gala2k [10]

70000000000 + 8818282828828

8 0
3 years ago
A student of the author earned grades of 92, 83, 77, 84, and 82 on herfive regular tests. She earned grades of 88 on the final e
goblinko [34]

The class is weighted as follows:

60% Regular Tests

10% Final Exam

15% Project

15% Homework

The total weighted points possible for the class are as follows:

(100+100+100+100+100)*.6 + 100*.1 + 100*.15 + 100*.15 = 340

To calculate her individual final weighted grade we plug in her scores for each category and complete the following computation:

(92+83+77+84+82)*.6 + 88*.1 + 95*.15 + 77*.15 = 285.4

So her weighted grade percent would be 285.4/340 = 83.9% which is a B.

8 0
3 years ago
Verify that P = Ce^t /1 + Ce^t is a one-parameter family of solutions to the differential equation dP dt = P(1 − P).
NemiM [27]

Answer:

See verification below

Step-by-step explanation:

We can differentiate P(t) respect to t with usual rules (quotient, exponential, and sum) and rearrange the result. First, note that

1-P=1-\frac{ce^t}{1+ce^t}=\frac{1+ce^t-ce^t}{1+ce^t}=\frac{1}{1+ce^t}

Now, differentiate to obtain

\frac{dP}{dt}=(\frac{ce^t}{1+ce^t})'=\frac{(ce^t)'(1+ce^t)-(ce^t)(1+ce^t)'}{(1+ce^t)^2}

=\frac{(ce^t)(1+ce^t)-(ce^t)(ce^t)}{(1+ce^t)^2}=\frac{ce^t+ce^{2t}-ce^{2t}}{(1+ce^t)^2}=\frac{ce^t}{(1+ce^t)^2}

To obtain the required form, extract a factor in both the numerator and denominator:

\frac{dP}{dt}=\frac{ce^t}{1+ce^t}\frac{1}{1+ce^t}=P(1-P)

3 0
3 years ago
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