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Tanya [424]
3 years ago
7

Use elimination to solve the system of equations. Show your work 5×-3y=6,2×+5y=-10.

Mathematics
2 answers:
Fofino [41]3 years ago
6 0

Answer:

5(5x-3y=6)

3(2x+5y=-10)

25x-15y=30

6x+15y=-30

31x= 0

x = 0

5(0)-3y=6

-3y=6

y= -2

(0,-2)

Vadim26 [7]3 years ago
3 0

Answer:x = 0, y = - 2

Step-by-step explanation:

The given system of equations is expressed as

5x - 3y = 6 - - - - - - - - - - - - 1

2x + 5y = - 10 - - - - - - - - - - - 2

We would eliminate x by multiplying equation 1 by 2 and equation 2 by 5. It becomes

10x - 6y = 12 - - - - - - - - - - - 3

10x + 25y = - 50- - - - - - - - - - - 4

Subtracting equation 2 from equation 1, it becomes

- 31y = 62

Dividing the Left hand side and the right hand side of the equation by

- 31, it becomes

- 31y/ - 31 = 62/- 31

y = - 2

Substituting y = - 2 into equation 1, it becomes

5x - 3 × - 2 = 6

5x + 6 = 6

5x = 6 - 6 = 0

x = 0

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Leona [35]

The value of the voltage is 18 - j volts if the current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms option (c) is correct.

<h3>What is a complex number?</h3>

It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.

We have:

The current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms.

As we know,

V = IR

V = (3 + j2)(4 - j3)

\rm V=\left(3\cdot \:4-2\left(-3\right)\right)+\left(3\left(-3\right)+2\cdot \:4\right)j

j² = -1 (complex part)

After simplification:

V = 18 - j  volts

Thus, the value of the voltage is 18 - j volts if the current in a circuit is 3 + j2 amps and the resistance is 4 - j3 ohms option (c) is correct.

Learn more about the complex number here:

brainly.com/question/10251853

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2 years ago
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Answer:

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