Question

Use elimination to solve the system of equations. Show your work 5×-3y=6,2×+5y=-10.

Answer 1

Answer:

5(5x-3y=6)

3(2x+5y=-10)

25x-15y=30

6x+15y=-30

31x= 0

x = 0

5(0)-3y=6

-3y=6

y= -2

(0,-2)

Answer 2

Answer:x = 0, y = - 2

Step-by-step explanation:

The given system of equations is expressed as

5x - 3y = 6 - - - - - - - - - - - - 1

2x + 5y = - 10 - - - - - - - - - - - 2

We would eliminate x by multiplying equation 1 by 2 and equation 2 by 5. It becomes

10x - 6y = 12 - - - - - - - - - - - 3

10x + 25y = - 50- - - - - - - - - - - 4

Subtracting equation 2 from equation 1, it becomes

- 31y = 62

Dividing the Left hand side and the right hand side of the equation by

- 31, it becomes

- 31y/ - 31 = 62/- 31

y = - 2

Substituting y = - 2 into equation 1, it becomes

5x - 3 × - 2 = 6

5x + 6 = 6

5x = 6 - 6 = 0

x = 0