Answer:
<u>Given :</u>
length offshore = CS=√(1+X^2)
Cable charged = 5000√(1+X^2)
onshore length = 4-X
laying cost = 3000(4-X)
total cost:
C=5000√(1+X^2) +3000(4-X)
DC/DX
= [5000*(0.5)*2X/{√(1+X^2)}]-3000=0... for optimum
5000X=3000√(1+X^2)
25X^2=3+3X^2
22X^2=3
X=√(3/22)
= 0.3693 miles
So, it would be laid offshore to S in a manner that
BS=X=0.3693 miles
Onshore=4-0.3693
=3.6307 miles
Answer:
m<1 = 105°
m<2 = 75°
Step-by-step explanation:
Since lines c and d are parallel to each other, therefore:
m<2 = 75° (corresponding angles are congruent)
m<1 + m<2 = 180° (linear angle pair)
Substitute
m<1 + 75° = 180°
Subtract 75 from both sides
m<1 = 180° - 75°
m<1 = 105°
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Answer:
136 m2 Option c
Step-by-step explanation:
136 m2
1 base = 6 × 7 = 42
2 sides = 2(7 × 5) = 70
2 triangles = 2(6 × 4
2
) = 24
SA = 42 + 70 + 24 = 136 m2
Answer:
B [2,∞)
Step-by-step explanation: