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4 years ago

10 divided by 2-(16 divided by 4) +14

Mathematics

2 answers:

ankoles [38]4 years ago

7 0

Answer:

Step-by-step explanation:

okay so you gotta use pemdas (p = parentheses, e = exponents, m = multiplication, d = division, a = addition, s = subtraction), but for the multiplication/division and addition/subtraction parts, if division or subtraction happens first then you must do it first rather than doing multiplication or addition first

10 / 2 -(16/4) + 14

10 / 2 -(4) + 14

5 - 4 + 14

1 + 14

kodGreya [7K]4 years ago

6 0

Answer:

Step-by-step explanation:

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Step-by-step explanation:

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25n < 1500 - 450

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3 years ago

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Solve triangle.A = 33°, a = 20, b = 13

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B = 20.7°

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Step-by-step explanation:

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3 years ago

Which phrase best defines erosion a) chemically breaking rocks apart b) physically breaking rocks apart c) moving bits of rock f

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Answer:

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3 years ago

It took 2.5 hours for the outside temperature to increase by 10°F. At this rate, predict how long it would take for the temperat

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3 years ago

The following describes a sample. The information given includes the five number summary, the sample size, and the largest and s

lys-0071 [83]

Answer:

$L= Q_1 - 1.5*IQR = 210 -1.5*40 =150$

$U= Q_3 + 1.5*IQR = 250 +1.5*40 =310$

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

Step-by-step explanation:

For this case we have the 5 number summary

(160,210,220,250,270)

So then we have:

minimum = 160 , Q1 = 210, Q2= Median=220, Q3 = 250, Max=270

If we find the interquartile range we got:

$IQR = Q_3 -Q_1 = 250-210 =40$

For this case we need to find the lower and upper limit with the following formulas:

$L= Q_1 - 1.5*IQR = 210 -1.5*40 =150$

$U= Q_3 + 1.5*IQR = 250 +1.5*40 =310$

And if we analyze the info provided we have 500 values

Tails: 160,165,167,171,175,...,268,269,269,269,270,270

So as we can see on the tails any values is <150 or >310 so then for this case we cannot consider as outliers any of the values on the tails of the distribution.

4 0

4 years ago