Answer:
$1 = 1.372 CD
Explanation:
Spot rate, 1$ = 1.3750 Canadian dollars
Canadian securities annualized return = 6%
U.S. securities annualized return = 6.5%
Term = 6 month ≅(180 days)
Forward exchange rate in 180 days, 1$ = Spot rate * (1+US rate*6/12) / (1+CD rate*6/12)
= 1.3750 CD * (1 + 6%*6/12) / (1 + 6.5%*6/12)
= 1.3750 CD * (1 + 0.03) / (1 + 0.0325)
= 1.3750 CD * 1.03/1.0325
= 1.371670702179177 CD
= 1.372 CD
So, the the U.S. dollar-Canadian dollar exchange rate in the 180-day forward market is $1 = 1.372 CD
Answer:
The answer is A
Explanation:
Companies should produce what customers want based on the marketing concept. Companies and customers are dependent on each other. Companies should focus on producing goods which consumers/customers want. These companies should think of what consumers want and the prices they would pay since it is the consumer that creates demand for goods and services that are produced by the company.
Therefore companies should produce only what consumers want else they would produce goods and services with little demand.
Answer:
about 68% of brand x’s batteries have a lifespan between 95.2 hours and 108.8 hours. about 68% of brand y’s batteries have a lifespan between 98.6 hours and 101.4 hours. the life span of brand y’s battery is more likely to be consistently close to the mean.
Explanation:
According to the empirical rule (68–95–99.7 rule) for a normal distribution, 68% of the data falls within the first standard deviation (μ ± σ).
Given for brand x, mean (μ) = 102 hours and standard deviation (σ) = 6.8 hours.
first standard deviation (μ ± σ) = 102 ± 6.8 = (95.2, 108.8)
about 68% of brand x’s batteries have a lifespan between 95.2 hours and 108.8 hours.
Given for brand y, mean (μ) = 100 hours and standard deviation (σ) = 1.4 hours.
first standard deviation (μ ± σ) = 100 ± 1.4 = (98.6, 101.4)
about 68% of brand x’s batteries have a lifespan between 98.6 hours and 101.4 hours.
Since the standard deviation of brand y is smaller than that of brand x, brand y battery is more likely to be consistently close to the mean
