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larisa86 [58]
3 years ago
13

Which equation represents a line which is parallel to the line y=8/5x−1?

Mathematics
2 answers:
mezya [45]3 years ago
6 0
An equation with the same slope and different y-intercept.
For example y=8/5x + 1 or y=8/5x-4
sertanlavr [38]3 years ago
5 0

ANSWER:

y=8/5x±R (Read explanation)

EXPLANATION:

Letting you know, you did not attach a picture. Thus, I'm guessing. Parallel lines mean that the slope will be the same, but the y-intercept is not. The slope here is 8/5x. That may stay the same, so here's the equation that we currently have:

y=8/5x (This can be the answer)

However, we must change the y-intercept which is -1 currently. You may change it to any real number. For example, 1, 0, -100, 10000, 999, etc. would work. So, the answer would be:

y=8/5x±R (R as All Real Numbers)

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4(28) = 4(20) + 4(?)
brilliants [131]
4(28) = 4(20) + 4(8)
The answer is 8
Because 28 is 20 and 8
4 0
3 years ago
What is the equation of the line that passes through the points (-3,0.5) and (3,-0.5)
MakcuM [25]

Answer:

y = -1/6x + 0

Step-by-step explanation:

Using the equation of line

y_2 - y_1 / x_2 - x_1 = y - y_1 / x_1

Using the information we are provided with

( -3, 0.5)(3 , -0.5)

y_1 = 0.5

x_1 = -3

x_2 = 3

y_2 = -0.5

-0.5 - 0.5 / 3- (-3) = y - 0.5 / x - (-3)

-0.5 - 0.5 / 3 +3 = y - 0.5 / x + 3

-1 / 6 = y - 0.5 / x + 3

Cross multiply

-1(x + 3) = 6(y - 0.5)

Open the brackets

-x - 3 = 6y - 3

-x - 3 + 3 = 6y

-x + 0 = 6y

Divide through by 6 to get y

Following the eqn y = mx + C

-x + 0 / 6 = 6y / 6

y = -x + 0 / 6

We can separate it

y = -x / 6 + 0/6

y = -1/6x + 0

Therefore, the equation of the line is

y = -1/6x + 0

7 0
3 years ago
6th grade math help. Can someone explain step by step how to solve #1 please
Alisiya [41]

Answer:

87

Step-by-step explanation:

start with the innermost parenthesis first

{4+3*[5+3*(8)]-4}

order of operations: multiply before you add

{4+3*[5+24]-4}

{4+3*[29]-4}

order of operations: multiply before you subtract

{4+87-4}

solve left to right

{91-4}

87

3 0
4 years ago
Find the given value of each angle for the following supplementary angles must add up to 180
juin [17]

<u>QUESTION :</u>

Find the given value of each angle for the following supplementary angles must add up to 180

\Large{\underline{\mathcal{ Given : }}}

  • one angle = (5x-13)°
  • another angle = (11x+65)°

\Large{\underline{\mathcal{Tofind : }}}

  • value of each angle

\Large{\underline{\mathcal{Solution : }}}

➱<em>ᴛʜᴇ ᴛᴡᴏ ᴀɴɢʟᴇs ʟɪᴇs ᴏɴ ᴛʜᴇ sᴀᴍᴇ ʟɪɴᴇ</em>

➱ѕσ ѕυм σƒ вσтн тнє αηgℓєѕ = 180°

therefore ,

⤳(5x-13)° + (11x+65)° = 180°

⤳5x -13° + 11x + 65° = 180°

⤳16x + 52° = 180°

⤳16x = 180° - 52°

⤳16x = 128°

⤳x = 128 /16

\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underline{\boxed{\sf{ x =  \frak{\red{ 8 }}}}}

hence ,

the two angles will be

⇛<u>ᴏɴᴇ ᴀɴɢʟᴇ</u> :

<em>➛</em>(5x-13)°

<em>➛</em>5(8) - 13

<em>➛</em>40 - 13

\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underline{\boxed{\sf{ᴏɴᴇ\: ᴀɴɢʟᴇ =  \frak{\red{ 27° }}}}}

⇛<u>ᴀɴᴏᴛʜᴇʀ ᴀɴɢʟᴇ</u> :

<em>➛</em><em> </em>(11x+65)°

<em>➛</em>11(8)+65

<em>➛</em>88 + 65

\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\underline{\boxed{\sf{ᴀɴᴏᴛʜᴇʀ\: ᴀɴɢʟᴇ = \frak{\red{ 153° }}}}}

6 0
3 years ago
Which of the following describes how to graph the line whose equation is y = 2/3x - 1?
pshichka [43]
You didnt write down the answers
5 0
4 years ago
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