Most invertebrates leave their young to fend for themselves while vertebrates help their young till they are ready
Answer:
it is because there is less oxygen and creatures need more oxygen to perform their work..
hope this helps you ☺️☺️
Answer:
The correct answer is A.) during transcription
Explanation:
The pairing during DNA replication and transcription is a little bit different. During replication, A pairs with T, T with A, C with G, and G with C. In transcription T is replaced by U so when there is nucleotide adenine is present in the DNA sequence than uracil will be added against it as complementary nucleotide in mRNA during transcription.
So here 5'-GAT-3' nucleotide sequence is present in DNA and after transcription the nucleotide sequence will be 5'-CUA-5' because U is added against A during transcription. Therefore the correct answer is A.
Answer:
c. accidental removal of the parathyroid glands during surgery
Explanation:
Parathyroid gland is found closely situated at the back of the thyroid gland in the human neck region. Regulation of serum calcium levels in the body is a major function of the parathyroid gland through the secretion of a hormone called parathyroid hormone or parathormone.
During the surgery conducted to remove the thyroid gland, it is very likely that the parathyroid glands were accidentally damaged or removed. This most likely led to the non--secretion of parathormone, which is responsible for secretion of calcium in the body, when calcium levels drop.
Answer:
Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).
Explanation:
<u>Datos disponibles:</u>
- Cruce entre peces naranjas y peces grises
- 50% de la F1 son peces grises
- Naranja dominante sobre gris
Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo para color gris <em>n</em>.
Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.
Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.
Cruce:
Parental) Nn x nn
Gametas) N n n n
Fenotipos) Naranja Gris
Cuadro de Punnett) N n
n Nn nn
n Nn nn
F1) 2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn
2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,
nn
50% de la progenie será color naranja (Nn)
50% de la progenie será color gris (nn)
