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NARA [144]
2 years ago
7

Algebra II Question - Give an ordered pair that is a solution of the system.

Mathematics
1 answer:
Blizzard [7]2 years ago
5 0

Answer:

(1,4)

or

(2,2)

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Do the ratios 10/8 and 16/20 form a proportion<br><br> Yes or no?
ziro4ka [17]

Answer:

No. Reduce 10/8 by dividing by 2. 10/8= 5, 8/2= 4. 10/8= 5/4. Reduce 16/20 by dividing by 4. 16/4= 4 , 20/4= 5. 16/20= 4/5.

6 0
3 years ago
The legs of a right triangle are 3 units and 6 units. What is the length of the hypotenuse? Round your answer to the nearest hun
garri49 [273]
C =\sqrt{3 ^{2} + 6  ^{2} } = 6.7082

Round 6.7082
6.71

6.71 is your answer
8 0
3 years ago
Read 2 more answers
A recipe says it produces the best sweet tea. In addition to using tea bags, the recipe calls for 12 cup of sugar for every 112
san4es73 [151]

Answer:

Step-by-step explanation:

Answer:

The relationship between the number of cups of water and sugar  in the recipe is w = ¹/₃(s)

Step-by-step explanation:

Given;

number of cups of sugar = s

number of cups of water = w

The relationship between the number of cups of water and sugar in this recipe is given as;

½ cup of sugar is proportional to 1 ½ cups of water

Therefore, the relationship between the number of cups of water and sugar  in the recipe is w = ¹/₃(s)

8 0
3 years ago
Select the graph of the solution. Click until the correct graph appears.
faust18 [17]

Answer:

C. is your answer

Step-by-step explanation:

4 0
2 years ago
A coin is flipped 10 times where each flip comes up either heads or tails. How many possible outcomes (a) contain exactly two he
Tems11 [23]

Answer:

a. 45

b. 176

c. 252

Step-by-step explanation:

First take into account the concept of combination and permutation:

In the permutation the order is important and it is signed as follows:

P (n, r) = n! / (n - r)!

In the combination the order is NOT important and is signed as follows:

C (n, r) = n! / r! (n - r)!

Now, to start with part a, which corresponds to a combination because the order here is not important. Thus

 n = 10

r = 2

C (10, 2) = 10! / 2! * (10-2)! = 10! / (2! * 8!) = 45

There are 45 possible scenarios.

Part b, would also be a combination, defined as follows

n = 10

r <= 3

Therefore, several cases must be made:

C (10, 0) = 10! / 0! * (10-0)! = 10! / (0! * 10!) = 1

C (10, 1) = 10! / 1! * (10-1)! = 10! / (1! * 9!) = 10

C (10, 2) = 10! / 2! * (10-2)! = 10! / (2! * 8!) = 45

C (10, 3) = 10! / 3! * (10-3)! = 10! / (2! * 7!) = 120

The sum of all these scenarios would give us the number of possible total scenarios:

1 + 10 + 45 + 120 = 176 possible total scenarios.

part c, also corresponds to a combination, and to be equal it must be divided by two since the coin is thrown 10 times, it would be 10/2 = 5, that is our r = 5

Knowing this, the combination formula is applied:

C (10, 5) = 10! / 5! * (10-5)! = 10! / (2! * 5!) = 252

252 possible scenarios to be the same amount of heads and tails.

6 0
3 years ago
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