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NARA [144]
2 years ago
7

Algebra II Question - Give an ordered pair that is a solution of the system.

Mathematics
1 answer:
Blizzard [7]2 years ago
5 0

Answer:

(1,4)

or

(2,2)

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Consider the ODE, dy dx = y 2 1 + x (2) subject to condition y = 1 when x = 0, use your Euler code from class (modified if neces
makkiz [27]

Answer:

Computation.

Step-by-step explanation:

I'm not really sure if that's the analytical solution of the inital value problem,

because y(0)=11-ln(1-0)(3)=11. Howevwer, let us procede with the given values...

Let us assume that we are going to use euler with n=2 (two steps) and h=0.2(the size of each step)

The update rules of the Euler Methode are

X_i = X_{i-1}+h=X_0+ih

m_i=\dfrac{dY}{dX} \biggr \rvert_{x_i} \\\\Y_{i+1}=m_i\cdot h+y_i

Since the initial value problem tells us that Y=1 when X=0, we know that

X_0=0 and that Y_0=1. Then, we have

X_0=0\\\\X_1=0.2\\\\X_2=0.4

and

Y_0=1\\\\m_0=21 \cdot Y_0 + X_0 \cdot 2=21 \cdot 1 + 0=21\\\\Y_1=0.2 \cdot 21 + 1 =5.2\\\\m_1=21 \cdot Y_1 + X_1\cdot 2=21 \cdot 5.2 + 0.2 \cdot 2=109.6\\ \\Y_2=m_1 \cdot h + Y_1 = 109.6 \cdot 0.2 + 5.2= 27.12

which gives us the points (0,1), (0.2, 5.2) and (0.4, 27.12).

Now, since we want to compare the analyticaland the Euler result, we first compute the value of y=11-ln(1-x)(3) for the values x=0, 0.2 and 0.4. We get that

y(0)=11-\ln(1-0)(3)=11-ln(1)(3)=11\\\\Y(1)=11-\ln(1-0.2)(3)=11.67\\\\Y(2)=11-\ln(1-0.4)(3)=12.53

and we compute Y(i)-Y_i for each i.

It holds

Y(0)-Y_0=11-1=10\\\\Y(1)-Y_1=11.67-5.2=6.47\\\\Y(2)-Y_2=12.53-27.12=-14.59

which tells us that we have a really bad approximation, as I already stated there must be a mistake in the analytical solution since the intial values don't coincide. Also note that the curve that we get using the euler methose is growing faster than the analitical solution.

4 0
3 years ago
What is 3 2/7 x 2 4/5 (Answer with a mixed number in simplest form) Thankyou!!
SCORPION-xisa [38]

Answer:

9 1/5

Step-by-step explanation:

3 2/7 * 2 4/5

Change to improper fractions

( 7*3+2)/7  * ( 5*2+4)/5

23/7 * 14/5

Rewriting

14/7 * 23/5

2 * 23/5

46/5

Changing back to a mixed number

5 goes into 45 9 times with 1 left over

9 1/5

7 0
3 years ago
Read 2 more answers
Rewrite 1 11/25 and 3 3/8 as a square or cube.<br><br> PLEASE PLEASE PLEASE HALLLLLPP, looool
GrogVix [38]

1 11/25

= 36/25 = (6/5)^2

and  

3 3/8

= 27/8 = (3/2)^3

5 0
3 years ago
8x2 + 7x - 4 <br> what is the factor
astraxan [27]

Answer:

19

Step-by-step explanation:

I think im wrong but give it a try

5 0
3 years ago
Need help on 9 and 10
Wewaii [24]
9.) The relation can not be a function only if the domain is the same. If you plot the points on a graph and use the Vertical Line Test(VLT) you would see that none of the points would be on the same line. It doesn't matter if the range is the same

10.)On the graph your y-intercept would be 2 so that is where you plot your first point. In order to find the slope you need to go up three spaces and one space to the left this is also known as "rise over run". *Remember you always go up spaces for "rise over run" but if the slope is positive then you go to the right and if its negative you go to the left.

I hope this helps love! :)
4 0
3 years ago
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