Answer:
El área del círculo que se encuentra en el cuadrado es de 78.5cm²
Step-by-step explanation:
Para resolver este ejercicio tenemos que pensar que un cuadrado tiene sus 4 lados iguales, por lo que todos sus lados medirán 10cm.
Ahora nos fijamos que necesitamos saber para calcular el área de un circulo
a = área
r = radio
π = 3.14
a = π * r²
como podemos ver no sabemos el valor del radio
como el circulo toca con los 4 lados del cuadrado sabemos que su radio sera la distancia del centro del cuadrado a cualquiera de los lados.
Entonces tenemos que dividir un lado por 2
10cm/2 = 5cm
El radio del circulo sera 5cm
Ahora que tenemos todos los datos podemos calcular el valor del área
a = 3.14 * (5cm)²
a = 3.14 * 25cm²
a = 78.5cm²
El área del círculo que se encuentra en el cuadrado es de 78.5cm²
Answer:
Step-by-step explanation:
Given that a dairy scientist is testing a new feed additive. She chooses 13 cows at random from a large population of cows. She randomly assigns nold = 8 to get the old diet, and nnew = 5 to get the new diet including the additive.
From the data given we get the following
N Mean StDev SE Mean
Sample 1 8 43 5.1824 1.832
Sample 2 5 73 21.0832 9.429
df = 11
Std dev for difference = 13.3689
a) Yes the two are independent. The two sets of cows randomly chosen are definitely independent. Paired means equal number should be there and homogeneous conditions should be maintained.
b) Enclosed
c) Comparison of two means is the test recommended here. Because independent samples are used.\
d) Test statistic= -3.1233
(because of unequal variances we use that method)
95% confidence interval = ( -56.6676 , -3.3324 )
p value <0.05 our alpha
So reject null hypothesis.
The two means are statistically significantly different.
First, lets create a equation for our situation. Let

be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>

<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is:

. So lets replace the values in our formula to find the average of our function:
![\frac{25(10)+100-[25(2)+100]}{10-2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B25%2810%29%2B100-%5B25%282%29%2B100%5D%7D%7B10-2%7D%20)



We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
5x 3y^3 2z
I know it is in standard form because there are no more like terms.
Part B: Polynomials are always closed under multiplication. Unlike with addition and subtraction, both the coefficients and exponents can change. The variables and coefficients will automatically fit in a polynomial. When there are exponents in a multiplication problem, they are added, so they will also fit in a polynomial.
Or,
Refer to the photos:
hope this help :)
Answer:
The answer to the equation is 16