5. 56° 94° 4.5% 1.5x
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A) Add three <em>line</em> segments (AD, CF, BE) to the <em>regular</em> hexagon.
B) The area of each triangle of the <em>regular</em> hexagon is 35.1 in².
C) The area of the <em>regular</em> hexagon is 210.6 in².
<h3>How to calculate the area of a regular hexagon</h3>
In geometry, regular hexagons are formed by six <em>regular</em> triangles with a common vertex. We decompose the hexagon in six <em>equilateral</em> triangles by adding three <em>line</em> segments (AD, CF, BE).The area of each triangle is found by the following equation:
A = 0.5 · (9 in) · (7.8 in)
A = 35.1 in²
And the area of the <em>regular</em> polygon is six times the former result, that is, 210.6 square inches.
To learn more on polygons: brainly.com/question/17756657
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Answer:
Step-by-step explanation:
Write down the slope-intercept form:
Where m is the slope and b is the y-intercept.
To turn the equation into slope-intercept form, isolate y on the left-hand side:
Rearrange the equation a bit: