Hope this helps
Answer :
Percentage increase = (279 - 180)/180 x 100% = 55%
Answer:
A. 3 * 6
Step-by-step explanation:
43 * 6 = (40 + 3) * 6 = 40 * 6 + 3 * 6
Answer:
Average rate of fall = 
Step-by-step explanation:
Since they give you an expression for the position of the object as a function of time, one can derive the average velocity of the object during the first 3 seconds of the fall by estimating the position of the object at time 0, the position of the object at time 3 seconds, finding the displacement of the object (distance covered) in that interval of time (via a subtraction of these two quantities), and finally dividing this change by the elapsed time (3 seconds) thus using the concept that velocity is the quotient between distance covered over the elapsed time:
Average rate of fall = (h(3) - h(0))/ 3
Average rate of fall =
Answer:
Rate = 0.7%
Step-by-step explanation:
Rate = Interest / (principal x time)
rate = 12.83 / ((550) x 12/4)
rate = 12.83 / (550 x 3)
rate = 12.83 / 1650
rate = 0.007
rate = 0.7%
Answer:
B. Centers: the sea turtles have a greater median age than the koi
D. Spreads: the ages of the koi are more spread out
Step-by-step explanation:
The difference between the center and spread of the data distribution of koi and sea turtles as shown in the dot plots are as follows:
==>Median:
For Koi, the median value is the 14th value represented by the 14th dot on the plot, which is 30.
The median value for koi is between the 7th and the 8th value represented by dots on the plot. The average of both values will give us 55 as the median value for koi.
Therefore, the median age of sea turtle is greater than that of koi.
==>Spread:
Koi has a range of 45 (60-15), while sea turtles have a range of 20 (65-45). Invariably, mere looking at the dot plot, we can conclude that ages of the koi are more spread out.
